Answer:
Step-by-step explanation:
x^3 + x^2 - x + 2 \ x + 4 = x^2 -3x + 11 - 42/(x+4)
Answer:
28.26
Step-by-step explanation:
I hope this helps!
Answer:
y x (2x +y) x (7x +y)
Step-by-step explanation:
14x^2y + 9xy^2 +y^3
(Factor the expression)
y x (14x^2 +9xy +y^2)
(Rewrite the expression)
y x (14x^2 + 7xy +2xy +y^2)
(Factor the expression)
y x (7x x(2x +y) + y x (2x +y) )
(Factor the expression)
y x (2x +y) x (7x +y)
:))
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
Answer:
86
Step-by-step explanation:
1,032 ÷ 12 = 86
86 containers would be needed.
