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Aneli [31]
3 years ago
11

What is 23x92? Give brainliest.

Mathematics
2 answers:
Volgvan3 years ago
8 0

Answer:

2116

Step-by-step explanation:

multiplication!

FrozenT [24]3 years ago
5 0

Answer:

2116

Step-by-step explanation:

Just look it up bro smh -_- but the answer is 2116 give me brainliest

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Step-by-step explanation:

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9.) hyperbole

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3 years ago
Let X, Y, and Z be jointly continuous random variables. Assume that all conditional PDFS and expectations are well defined. E.g.
BabaBlast [244]

Answer:

True

Step-by-step explanation:

Given that X,Y and Z are jointly continuous random variables

For : E [g(Y) | Y= x] = ∫g(y) fY| X ( y|x ) dy

For all choices of g the function is true given that g(y) = a random variable

A random variable is a variable with an unknown value it can be said to assign values to an experimental outcome.

7 0
3 years ago
Solve the system (x-1)²+(y-2)²=2² and y=2x+2.
Likurg_2 [28]

Answer:

  (x, y) = (-0.6, 0.8)  or  (1, 4)

Step-by-step explanation:

Use the second equation to substitute for y in the first.

 (x -1)² +((2x +2) -2)² = 4

  x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses

  5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms

Now we can rearrange the middle term to ease factoring by grouping.

  (5x² -5x) +(3x -3) = 0

  5x(x -1) +3(x -1) = 0

  (5x +3)(x -1) = 0

The values of x that make these factors zero are ...

  x = -3/5, x = 1

The corresponding values of y are ...

  y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5

  y = 2(1) +2 = 4 . . . . . . . . for x = 1

The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).

___

A graphing calculator verifies these solutions.

3 0
3 years ago
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