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OlgaM077 [116]
2 years ago
14

A solution is prepare using 45.2 g of an unknown (nonelectrolyte) dissolved in 476.4 g of water. The freezing point depression

Chemistry
1 answer:
Ray Of Light [21]2 years ago
6 0

Answer:

94.4g/mol is molar mass of the unknown

Explanation:

Based on the freezing point depression equation:

ΔT = Kf*m*i

<em>Where ΔT is the depression in freezing point (1.87°C)</em>

<em>Kf is freezing point depression constant of water (1.86°Ckg/mol)</em>

<em>And i is Van't Hoff factor (1 for nonelectrolyte solutes)</em>

<em />

Replacing:

1.87°C = 1.86°CKg/mol*m*i

1.005mol/kg solvent = m

Using the mass of the solvent we can find the oles of the nonelectrolyte:

1.005mol/kg solvent * 0.4764kg = 0.479moles

Molar mass is defined as the ratio between mass of a substance in grams and moles, that is:

45.2g / 0.479mol =

<h3>94.4g/mol is molar mass of the unknown</h3>
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