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Pachacha [2.7K]
3 years ago
12

substances x and y are both nonpolar. if the volatility of x is higher than that of y, what is the best explanation?

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0
It may have less attractive forces between their atoms
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HELP ME PLEASE WILL GIVE MORE POINTS AND BRAINLIEST!!
Sedbober [7]

✅Show work regardless if student got answer  correct or incorrect

q = mC∆T

q = (30.0g)(0.900J/goC)(50oC)

q = 1350 J

So, the right answer is 1350 J

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2 years ago
Can a cold front warm air moves which direction
Katena32 [7]
East is the cold front
6 0
3 years ago
How many equivalents are present in 10 g of Ca2+? <br> 1 <br> 0.5 <br> 1.5 <br> 2
Lynna [10]

0.5

Explanation:

Given parameters:

Mass of Ca²⁺ = 10g

unknown:

Equivalent weight = ?

Solution:

Equivalent weight that is the amount of electrons which a substance gains or loses per mole.

Ca²⁺ has +3 charge

It lost 2e⁻;

therefore;

  In 1 mole of  Ca²⁺, we have 2 equivalent weight

1 mol  Ca²⁺ = 2eq. wts. 

1 mol Ca x (40 g / 1 mol ) x (1 mol / 2 eq.wts.) = 20.0 g = 1 eq.wt. 

Therefore;

10.0 g  Ca²⁺ x (1 eq.wt. / 20.0 g) = 0.5 eq.wts.

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8 0
3 years ago
NEEEEEEEEEEEEEEEEED HELP
lakkis [162]
<h3> <u>Answer</u></h3>

4. loses 2 electrons

<h3><u>EXPLANATION</u></h3>

Mg²+ has 10 electrons while Mg has 12 electrons.

7 0
2 years ago
How many grams of fluorine are needed to react with 8.5g of phosphorus?
love history [14]

Step 1: write the equation:

                                          P₄(s) + 6F₂(g) → 4PF₃(g) 


Step 2: Molar mass of P₄ = 30.97 g/mol × 4 = 123.88 g/mol


Step 3: Number of moles of phosphorus

                                                    n = m/M 

                                                    n = 8.5 g/123.88g/mol

                                                    n = 0.07 moles


Step 4: 0.07 × 12 = 0.84 moles of fluorine.

Fluorine is diatomic gas so we multiplied the number of moles by 12.


Step 5: To find the mass of fluorine we multiply the number of moles with the molar mass.

                            Mass of fluorine = 0.84 ×  228 

                                                        = 191.52 grams.

4 0
3 years ago
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