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SVEN [57.7K]
3 years ago
8

Find the slope of the linear function that passes through the points (−1, 5) and (8, 11).

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

6 over  9

Step-by-step explanation:

y2-y1 over x2-x1

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emmasim [6.3K]
150 is your correct answer 
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3 years ago
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Which group has more people?
Vilka [71]

Answer:

Daytime people.

Step-by-step explanation:

Evening people have 125.

Daytine people have 140.

4 0
3 years ago
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PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
A particle is moving with the given data. find the position of the particle. a(t) = 13 sin(t) + 4 cos(t), s(0) = 0, s(2π) = 10
alekssr [168]

OK so we need to find the function v(t) which will tell us where the particle is at any given time.

We know that the derivative of distance is speed and the derivative of speed is acceleration.

In this case we need to work backwords and find the integrals.


a(t) = 13 sin(t) + 4 cos(t)

s(t)= integral of above = 13(-cos(t)) + 4(sin(t)) + C

v(t)= integral of above = -13sin(t) -4cos(t) +Ct + D


Now I believe you have incorrect initial conditions

s(0) = 0, s(2π) = 10

As cos and sin functions have the same value at 0 and 2Pi the above cannot be true.

My guess is that one is s(0) and the other is v(2Pi) or the other way round.

These initial conditions will determine the value of the two constants: C and D.


Hope this helps.

3 0
4 years ago
Simplify the expression <br>(2x-6) - (4x+4)​
ollegr [7]

Answer:

-2x - 10

Step-by-step explanation:

(2x-6) - (4x+4)​    multiply (4x+4)​  by -1   -1(4x + 4) = -4x - 4

2x - 6 - 4x - 4  Re-arrange

2x - 4x - 6 - 4

-2x - 10

5 0
3 years ago
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