2NH4ClO4 --------> N2 + Cl2 + 2O2 + 4H2O
from reaction 2 mol 1 mol
given x mol 0.10 mol
Proportion:
<u>2 mol NH4ClO4 </u>= <u>1 mol Cl2</u>
x mol NH4ClO4 0.10 mol Cl2
x= (2*0.10)/1 = 0.20 mol NH4ClO4
The reactants are all the formulas to the left of the arrow, which are:
hcI(aq) nahco3(aq)
Molarity= (number of moles of that substance) / (Volume of solution in litres)
7= (number of moles of HCl) / 0.05
Thus,
Number of moles of HCl = 7 x 0.05 = 0.35
The number of moles of HCl will remain unchanged.
Now, for new solution,
0.35= 0.35 / (New volume of solution in litres)
Thus,
New volume = 1 litre
Thus, amount of water added = 1- 0.05 litre = 5.0 M
Answer: By Stoichiometry, 3 moles of chlorine gas reacts with 6 moles of sodium hydroxide solution to form 5 moles of sodium chloride, 1 mole of sodium chlorate (V) and 3 moles of water. Hence, the reaction between chlorine gas and hot, concentrated NaOH solution yields Sodium chloride and sodium chlorate(V).
Explanation: Hope it helps :)