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sergij07 [2.7K]
3 years ago
15

Reaction of hypochlorous acid and ammonia is product-favored system at equilibrium. Answer A: Reaction of hypochlorous acid and

ammonia is product-favored system at equilibrium. A Reaction of hypochlorous acid and ammonia is reactant-favored system at equilibrium. Answer B: Reaction of hypochlorous acid and ammonia is reactant-favored system at equilibrium. B Reaction of hypochlorous acid and ammonia yields pH 7.00. Answer C: Reaction of hypochlorous acid and ammonia yields pH 7.00. C No reaction occurs between hypochlorous acid and ammonia. Answer D: No reaction occurs between hypochlorous acid and ammonia. D Further data are needed to draw a conclusion about a prospective reaction.
Chemistry
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

A. True

B. False

Explanation:

Reaction between hypochlorous acid and ammonia does not yields a Ph value of 7.00 , this value is defined to water and no other reaction can yield exactly this Ph value. The acid reaction will give a Ph value below 7 while a base reaction will give Ph value of above 7.

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#12 please! worth 40 points
Serga [27]
Okay so because of the difference in density a simple method for telling the difference between the two is to put a sample in a container with oil, because water has a higher density than the oil it would sink to the bottom but alcohol on the other hand is lighter than oil and would float on top of the oil.

However with this question I think that what you would do is use the ice to find out what the substance is, it would float on top of the liquid if it were water because the water is denser than ice but the ice would sink if it was alcohol because the alcohol is less dense than ice. 


I hope this helps you, good luck : )

3 0
3 years ago
Why is peer review an important part of the scientific process?
BigorU [14]

I would say B.

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3 0
3 years ago
Read 2 more answers
Which total mass is the smallest?
andreev551 [17]
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neutrons 1.6749*10^-27 kg
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8 0
3 years ago
Explain the relationship between the following terms: eutrophication, nutrients, dissolved oxygen leads, and algae.
makvit [3.9K]

Answer:

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6 0
3 years ago
4.1 moles of sodium carbonate to molecules of sodium carbonate.​
docker41 [41]
<h3>Answer:</h3>

2.47 × 10^24 molecules

<h3>Explanation:</h3>

One mole of a compound contains molecules equivalent to the Avogadro's number, 6.022 × 10^23.

That is, 1 mole of a compound =  6.022 × 10^23 molecules

Therefore,

1 mole of Na₂CO₃ = 6.022 × 10^23 molecules

Thus, we can calculate the number of molecules in 4.1 moles of Na₂CO₃

we get,

 = 4.1 moles × 6.022 × 10^23 molecules

 = 2.47 × 10^24 molecules

Hence, 4.1 moles of Na₂CO₃ contains 2.47 × 10^24 molecules

3 0
4 years ago
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