Answer:
As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.
Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.
Below is the structures of possible minor products and the NMR spectrum respectively.
Possible Product A:
If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.
Possible Product B:
If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.
Possible Product C:
If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.
Possible Product D:
If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.
Yes simplify. Anybody educated in chemistry can look at the equation and see that you have Fe+2 and CO3-2 combined to make FeCO3. But you don't need the 2s. Always simplify the subscripts.
By the way, the equation is not fully balanced. Check KBr.
A precipitate will be formed through the double displacement method in chemical reactions. The chemical equation would be:
Na2CO3 + AgNO3 ----> NaNO3 + Ag2CO3.
Balancing would result to:
<span>Na2CO3 + 2AgNO3 ----> 2NaNO3 (aq)+ Ag2CO3.
</span>
Ag2CO3 is the precipitate formed. It is yellow in color but due to the presence of elemental silver, it is a bit grayish.