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2 years ago

Heat is the movement of thermal energy from one place to another. true or false

Chemistry

2 answers:

kykrilka [37]2 years ago

8 0

Thermal energy that is transferred from one substance to another; moves from warmer to cooler objects. So True.

yuradex [85]2 years ago

6 0

Answer: The given statement is true.

Explanation:

When particles of a substance or object attain internal energy due to the kinetic energy of its particles then this energy is known as thermal energy.

So, when two objects of different temperature are kept in contact with each other then this thermal energy flows from hotter object to cooler object.

This is known as heat is flowing from hot object to cool object.

Hence, we can conclude that the statement heat is the movement of thermal energy from one place to another, is true.

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Write the first and second ionization equations for H2SeO3 please.

IRISSAK [1]

As a diprotic acid, the H₂SeO₃ can ionize by step. First step is H₂SeO₃ =(reversible reaction) H⁺ + HSeO₃⁻. And second step is HSeO₃⁻ =(reversible reaction) H⁺ +SeO₃ ²⁻.

3 0

2 years ago

The work function for metallic potassium is 2.3 eV. Calculate the velocity in km/s for electrons ejected from a metallic potassi

mote1985 [20]

Answer:

932.44 km/s

Explanation:

Given that:

The work function of the magnesium = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, work function = $2.3\times 1.6022\times 10^{-19}\ J=3.68506\times 10^{-19}\ J$

Using the equation for photoelectric effect as:

$E=\psi _0+\frac {1}{2}\times m\times v^2$

Also, $E=\frac {h\times c}{\lambda}$

Applying the equation as:

$\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

m is the mass of electron having value $9.11\times 10^{-31}\ kg$

$\lambda$ is the wavelength of the light being bombarded

$\psi _0=Work\ function$

v is the velocity of electron

Given, $\lambda=260\ nm=260\times 10^{-9}\ m$

Thus, applying values as:

$\frac{6.626\times 10^{-34}\times 3\times 10^8}{260\times 10^{-9}}=3.68506\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2$

$3.68506\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{260\times \:10^{-9}}$

$\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=7.64538\times 10^{-19}-3.68506\times 10^{-19}$

$\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=3.96032462\times 10^{-19}$

$v^2=0.869446\times 10^{12}$

v = 9.3244 × 10⁵ m/s

Also, 1 m = 0.001 km

5 0

3 years ago

Neutralization is a process that occurs whenever an acid reacts with a base in the mole ratios specified by the balanced equatio

labwork [276]

The factors that can determine the outcome of a "neutralization reaction" include:
__________________________________________________________
1) temperature;

2) concentration (of the solution);

3) type of acid used;

4) type of alkali used;

5) type of reaction;
(e.g. whether the reaction is "endothermic" or "exothermic");
_____________________________________________________

7 0

3 years ago

Which statement accurately describes why air pressure decreases as altitude increases? As you increase altitude the temperature

labwork [276]

Answer:

The correct answer is " As you increase altitude, Earth's gravity is not acting as greatly as when closer to Earth's surface so the weight of air molecules decrease, which also in turn decreases air pressure."

Explanation:

As altitude increases air becomes rarefied. At higher altitudes there is less Earth's gravity acting on the air molecules than at areas close the earth surface. Air pressure is the weight of air acting per unit surface area. At higher altitudes as the weight of air decreases due to reduced gravitational pull the air pressure also decreases.

3 0

2 years ago

Describe how to do a flame test on a sample of a salt

Katen [24]

Answer:Hope this helps!

Explanation:

You can use a flame test to help identify the composition of a sample. The test is used to identify metal ions (and certain other ions) based on the characteristic emission spectrum of the elements. The test is performed by dipping a wire or wooden splint into a sample solution or coating it with the powdered metal salt. The color of a gas flame is observed as the sample is heated. If a wooden splint is used, it's necessary to wave the sample through the flame to avoid setting the wood on fire. The color of the flame is compared against the flame colors known to be associated with the metals.

4 0

3 years ago