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NeTakaya
2 years ago
14

plz tell fast oktwo paragraphs describing the advantages and disadvantages of living in the town.plz tell​

Physics
1 answer:
mars1129 [50]2 years ago
3 0

Answer:

There are advantages and disadvantages to living in a small town. You are likely to have more frequent contact with neighbors in a small town than you would in a larger town or city, so it is important to take into account the pros and cons of having privacy. Also take into consideration other factors, including your plans for a family, the career opportunities, your finances, the schools and entertainment options. Your personality will determine whether a small town offers advantages or disadvantages.

Privacy

Many people who reside in small towns enjoy the closeness of knowing their neighbors and the details of neighbors' lives. If a baby is born, a child is ill or a relative dies, people in small towns often want to know about it and be there for you. This can be an advantage, especially if you are lacking a family of your own or enjoy a great deal of socializing. However, if you would rather keep the details of your life to yourself and turn your nose up at idle gossip, small town living might not be for you.

Finances

Jobs can be hard to come by in small towns. You might be required to commute out of town to work but then return to a peaceful environment at the end of a busy day. Housing might be cheaper in small towns, although commuting costs might be higher. Food and child care expenses might be reduced as people are more likely to have gardens and share produce or take turns watching each other's children.

Recreation

One of the disadvantages of a small town is not being close to amusement parks, zoos or museums. However, people in small towns tend to come together during town picnics, festivals or fairs. Depending on your preferences, small towns might provide a relaxed, slower pace when it comes to entertainment compared to the hustle and bustle of a city, where there is constant movement, commotion and entertainment at every corner.

Schools

In a small town, class sizes are usually smaller and teachers and students can get to know each other and their fellow classmates on a deeper level. Many small towns have schools that receive national academic awards or are the highest achieving district in their states. CNN Money ranked Louisville, Colorado as the number one small town in America in 2011 and the school system is academically ranked among the top three in the Denver area. However, some of these towns noted high taxes as a trade-off for the outstanding school systems.

Explanation:

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A jumbo jet weighing 65,000 kg Is accelerating at 3 m/s^2 while its jet engines are putting out 200000 N of thrust.
sveticcg [70]

Answer:

Fa = 5000 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

Let's assume that the movement of the plane is to the right, any movement or force to the right will be marked with a positive sign, while any force or movement to the left, will be taken as negative.

The force of the turbine drives the plane to the right, therefore it is positive, the acceleration is constant and keeps the movement to the right, therefore it is positive, the wind drag force tries to prevent the movement of the plane to the left therefore it is negative, with this analysis we deduce the following equation.

ΣF = m*a

where:

ΣF = sum of forces [N] (units of Newtons)

m = mass = 65000 [kg]

a = acceleration = 3 [m/s²]

Fa = force exerted by the air [N]

200000 - Fa = 65000*3

Fa = 200000 - (3*65000)

Fa = 5000 [N]

8 0
3 years ago
What is 3*10^-6 divided by 2.5*10^6 expressed in standard notation?​
givi [52]

Answer:

1.2 x 10^-12

Explanation:

3/2.5 x 10^-6/10^6

1.2 x 10^-6 x 10^-6

1.2 x 10^-12

6 0
2 years ago
Explain whether the unit of work is a fundamental or derived unit
klasskru [66]

Answer:

answer here

Explanation:

the unit of work is fundamental unit because it doesn't depend on other units.

__________________

Thx

6 0
2 years ago
Read 2 more answers
If two micro coulomb of charge is flowing in a circuit for 5 minutes. What is the amount of current in the circuit?
Murrr4er [49]

Answer:

6.67×10¯⁹ A

Explanation:

From the question given above, the following data were obtained:

Quantity of electricity (Q) = 2 μC

Time (t) = 5 mins

Current (I) =?

Next, we shall convert 2 μC to C. This can be obtained as follow:

1 μC = 1×10¯⁶ C

Therefore,

2 μC = 2 μC × 1×10¯⁶ C / 1 μC

2 μC = 2×10¯⁶ C

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 secs

Therefore,

5 min = 5 min × 60 sec / 1 min

5 mins = 300 s

Finally, we shall determine the current in the circuit. This can be obtained as follow:

Quantity of electricity (Q) = 2×10¯⁶ C

Time (t) = 300 s

Current (I) =?

Q = It

2×10¯⁶ = I × 300

Divide both side by 300

I = 2×10¯⁶ / 300

I = 6.67×10¯⁹ A

Thus, the current in the circuit is 6.67×10¯⁹ A

4 0
2 years ago
a whistle you use to call your hunting dog has a frequency of 21 khz, but your dog is ignoring it. you suspect the whistle may n
laila [671]

To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as

f = f_0 (\frac{v-v_0}{v})

Here,

f_0 = Original frequency

v_0 = Velocity of the observer

v = Velocity of the speed

Our values are,

v = 340m/s \rightarrow \text{Speed of sound}

f = 20kHz \rightarrow \text{Apparent frequency}

f_0 = 21kHz \rightarrow \text{Original frequency}

Using the previous equation,

f = f_0 (\frac{v-v_0}{v})

Rearrange to find the velocity of the observer

v_0 =v (1-\frac{f}{f_0})

Replacing we have that

v_0= (340m/s)(1-\frac{20kHz}{21kHz})

v_0 = 16.19m/s

Therefore the velocity of the observer is 16.2m/s

4 0
2 years ago
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