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3 years ago

Please help I’ll mark you as brainliest if correct

Mathematics

1 answer:

Alex787 [66]3 years ago

6 0

Answer:

2nd one

Step-by-step explanation:

If u put all of them together and then multiply, you'll get that answer :B

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Please helpppppppjshdbdjshjdbdjdjsbdnd

melamori03 [73]

The answer is the first one so A

7 0

3 years ago

Solve the system by substitution: <br> 3x + 2y = 26<br> Y=x + 3

Orlov [11]

Answer:

x = 4

Step-by-step explanation:

3x + 2y = 26

y = x + 3

Plug in the equation for y

3x + 2(x + 3) = 26

Multiply the 2 with what is in the parantheses

3x + 2x + 6 = 26

Combine like terms and solve for x

5x + 6 = 26

5x = 20

x = 4

5 0

3 years ago

Read 2 more answers

What is the answer to a small box holds 75% as much as a large box if the small box holds 36 units how much does a large box hol

xxMikexx [17]

Answer:

large box will hold 48 units.

Step-by-step explanation:

Let the holding capacity of large box = x

According to given scenario:

75% of x = 36

0.75 x = 36

Dividing both sides by 0.75 we get:

x = 36/0.75

x = 48 units

So the large box will hold 48 units.

i hope it will help you!

4 0

3 years ago

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), what is C' if

Anestetic [448]

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

5 0

3 years ago

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical

Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

$p = \frac{78}{100} = 0.78$

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

4 0

3 years ago