Answer:
256.68m
Explanation:
that is the procedure above
Answer:
The mass of the another block is 60 kg.
Explanation:
Given that,
Mass of block M= 100 kg
Height = 1.0 m
Time = 0.90 s
Let the mass of the other block is m.
We need to calculate the acceleration of each block
Using equation of motion
![s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Put the value into the formula
![1.0=0+\dfrac{1}{2}\times a\times(0.90)^2](https://tex.z-dn.net/?f=1.0%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%280.90%29%5E2)
![a=\dfrac{2\times1.0}{(0.90)^2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B2%5Ctimes1.0%7D%7B%280.90%29%5E2%7D)
![a=2.46\ m/s^2](https://tex.z-dn.net/?f=a%3D2.46%5C%20m%2Fs%5E2)
We need to calculate the mass of the other block
Using newton's second law
The net force of the block M
![Ma=Mg-T](https://tex.z-dn.net/?f=Ma%3DMg-T)
....(I)
The net force of the block m
![ma=T-mg](https://tex.z-dn.net/?f=ma%3DT-mg)
Put the value of T from equation (I)
![ma=Mg-Ma-mg](https://tex.z-dn.net/?f=ma%3DMg-Ma-mg)
![m(a+g)=M(g-a)](https://tex.z-dn.net/?f=m%28a%2Bg%29%3DM%28g-a%29)
![m=\dfrac{M(g-a)}{(a+g)}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BM%28g-a%29%7D%7B%28a%2Bg%29%7D)
Put the value into the formula
![m=\dfrac{100(9.8-2.46)}{2.46+9.8}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B100%289.8-2.46%29%7D%7B2.46%2B9.8%7D)
![m=59.8\ \approx60\ kg](https://tex.z-dn.net/?f=m%3D59.8%5C%20%5Capprox60%5C%20kg)
Hence, The mass of the another block is 60 kg.
Answer:If an object's speed changes, or if it changes the direction it's moving in,
then there must be forces acting on it. There is no other way for any of
these things to happen.
Once in a while, there may be a group of forces (two or more) acting on
an object, and the group of forces may turn out to be "balanced". When
that happens, the object's speed will remain constant, and ... if the speed
is not zero ... it will continue moving in a straight line. In that case, it's not
possible to tell by looking at it whether there are any forces acting on it
By definition, acceleration is the change in velocity per change of time. As time passes by, the time increases in value. So, when the acceleration is decreasing while the time is increasing, then that means that the change of velocity is also decreasing with time. So, optimally, the initial velocity and the velocity at any time are very relatively close to each other,