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3 years ago

11

the sale price of apples at a lickal grocery store is $1.35 for the first pound and $1.10 for each additional pound. which funct

ion rule shows how the cost of apples y depends on the number of pounds x

1 answer:

borishaifa [10]3 years ago

8 0

C(y) = 1.35 + 1.10p(x)

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Solve for x.<br><br> 3x - 13 = 2<br><br> (SHOW YOUR WORK)

Eddi Din [679]

3x-13=2

move -13 to the other side

sign changes from -13 to +13

3x-13+13=2+13

3x=2+13

3x=15

divide both sides by 3 to get x by itself

3x/3=15/3

cross out 3 and 3, divide by 3 and then becomes 1*1*x=x

x=15/3

x=5

answer:

x=5

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3 years ago

Find the volume of a rectangular prism with a height of 18 if the base has a length of 9 and a width of 17.

docker41 [41]

Hey there! I'm happy to help!

To find the volume of a rectangular prism, you simply multiply each of the three different sides!

18×9×17=2754

Therefore, the volume of this rectangular prism is c. 2754 units cubed.

Now you can find the volume of a rectangular prism! Have a wonderful day!

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4 years ago

MATH.... TRIANGLE JKL HAS VERTICES...

7nadin3 [17]

<h3>Answer: Choice (d)</h3>

Explanation:

To reflect over the y axis, we apply this rule

$(x,y) \to (-x,y)$

which says to flip the sign of the x term but keep the y coordinate the same.

So that means something like J(-2,5) becomes J ' (2, 5). The other points are handled in the same fashion and that leads us to choice (d). Points on the y axis will stay where they are.

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3 years ago

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Firdavs [7]

Answer:

1) Your slope should be 1/5

2) Your slope should be $\frac{-3}{2}$

3) Your slope should be 1/2

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3 years ago

Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

$z=\sqrt{\dfrac{1371}{196}}\sin t$

(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

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4 years ago