There are 3 molecules of H2.
There are 2 atoms of nitrogen presented in the reactants.
2 moles of NH3 are formed.
To determine the number of grams of potassium hydroxide, we need to know what is the units of parts per million and what it means. Then, we can multiply the grams of solution to obtain the grams KOH. Parts per million (ppm) means that there is 1 mass unit of solute per 1 million mass units of solution. Therefore,
300 ppm = 300 g KOH / 1000000 g solution
mass KOH = 300 g KOH / 1000000 g solution (1000 g solution)
mass KOH = 0.3 g KOH
When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.
<h3>How do we calculate gained energy?</h3>
The amount of energy which is gained by any sample will be calculated as:
Q = mcΔT, where
Q = gained energy
m = mass of sample = 10g
c = specific heat of water = 4.18 J/g°C
ΔT = change in temperature = 18 - 13 = 5°C
On putting values we get
Q = (10)(4.18)(5)
Q = 209 Joules
Hence required amount of energy is 209 joules.
To know more about gained energy, visit the below link:
brainly.com/question/21704399
Well the sun wouldn't be up yet it would be dark and when you wouldn't be able to see it they would see it in the sky
Answer:
209.98 g of NaOH
Explanation:
We are given;
- Volume of HCl as 3 L
- Molarity of HCl as 1.75 M
We are required to calculate the mass of NaOH required to completely neutralize the acid given.
First, we write a balanced equation for the reaction between NaOH and HCl
That is;
NaOH + HCl → NaCl + H₂O
Second, we determine the number of moles of HCl
Number of moles = Molarity × Volume
= 1.75 M × 3 L
= 5.25 moles
Third, we use the mole ratio to determine the moles of NaOH
From the reaction,
1 mole of NaOH reacts with 1 mole of HCl
Therefore;
Moles of NaOH = Moles of HCl
= 5.25 moles
Fourth, we determine the mass of NaOH
Molar mass of NaOH = 39.997 g/mol
Mass of NaOH = 5.25 moles × 39.997 g/mol
= 209.98 g
Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl
