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IrinaVladis [17]
3 years ago
11

The poem "from blossom" inspires readers to appreciate the the joy of the presebt

Chemistry
1 answer:
lana [24]3 years ago
7 0
No... From blossom. Is your answer
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Write a goal of the lab or the question you tried to answer
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Answer:

I need to see the lab

Explanation:

7 0
3 years ago
5. A gas occupies 2000. Lat 100.0 K and exerts a pressure of 100.0 kPa. What volume will
Anna [14]

Answer:

4000 L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 2000 L.

Initial temperature (T1) = 100 K.

Initial pressure (P1) = 100 kPa.

Final temperature (T2) = 400 K.

Final pressure (P2) = 200 kPa.

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using the general gas equation as follow:

P1V1/T1 = P2V2/T2

100 x 2000/100 = 200 x V2/400

Cross multiply to express in linear form.

100 x 200 x V2 = 100 x 2000 x 400

Divide both side by 100 x 200

V2 = (100 x 2000 x 400)/(100 x 200)

V2 = 4000 L

Therefore, the new volume of the gas is 4000 L

5 0
3 years ago
What did the early atomic theory
Virty [35]

Answer:B

Explanation:

The early theory says that atom Is the smallest indivisible particle. Which was later proven to contain electron neutron and proton

7 0
4 years ago
Read 2 more answers
A mixture of N2, O2, and Ar has mole fractions of 0.25, 0.65, and 0.10, respectively. What is the pressure of N2 if the total pr
s344n2d4d5 [400]

Answer:

Partial pressure of nitrogen gas is 0.98 bar.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.

P=p_{N_2}+p_{O_2}+p_{Ar}

p_{N_2}=P\times \chi_{N_2}

p_{O_2}=P\times \chi_{O_2}

p_{Ar}=P\times \chi_{Ar}

where,

P = total pressure = 3.9 bar

p_{N_2} = partial pressure of nitrogen gas  

p_{O_2} = partial pressure of oxygen gas  

p_{Ar} = partial pressure of argon gases  

\chi_{N_2} = Mole fraction of nitrogen gas  = 0.25

\chi_{O_2} = Mole fraction of oxygen gas  = 0.65

\chi_{Ar} = Mole fraction of argon gases = 0.10

Partial pressure of nitrogen gas :

p_{N_2}=P\times \chi_{N_2}=3.9 bar\times 0.25 =0.98 bar

Partial pressure of oxygen gas :

p_{N_2}=P\times \chi_{O_2}=3.9 bar\times 0.65=2.54 bar

Partial pressure of argon gas :

p_{N_2}=P\times \chi_{Ar}=3.9 bar\times 0.10=0.39 bar

7 0
4 years ago
Choose the solvent below that would show the greatest boiling point elevation when used to make a 0.10 m nonelectrolyte solution
postnew [5]

Answer is: 1) ccl4, kb = 29.9°c/m, carbon tetrachloride has the greatest boiling point elevation.

The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.

<span> ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant.
b - molality of the solution.
So the highest boiling poing elevation will be for solution with highest ebullioscopic constant because molality is the same.</span>

5 0
3 years ago
Read 2 more answers
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