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Aleksandr-060686 [28]
3 years ago
15

A value that describes how heavy an object is and is related to the force of gravity is

Physics
2 answers:
Slav-nsk [51]3 years ago
6 0

The heaviness of an object with the relation to force of gravity, is described by the ‘weight’

<u>Explanation: </u>

The heaviness of the object is referred to the mass of the object. When the mass of the object is concerned it is taken in space or vacuum where force of gravity do not exist.

Therefore, to value the actual heaviness of the object, mass is multiplied by the component of force of gravity, is termed as weight.  

\bold{\text { Weight }=\text { Mass } \times \text { Accleration due to gravity }}

Natasha_Volkova [10]3 years ago
3 0

Answer:

mass

Explanation:

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Mkey [24]

Answer : Celestial or azimuth - altitude

Explanation :  

Celestial : The celestial coordinates that are analogous to longitude and latitude are called RA and Dec.

RA = Right Ascension

Dec = Declination

RA is the measured in unit of time and Dec is measured in degree.

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Azimuth - altitude :  Azimuth - altitude define the location of an object in the sky.

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valentinak56 [21]

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3 years ago
A 1.8 kg uniform rod with a length of 90 cm is attached at one end to a frictionless pivot. It is free to rotate about the pivot
Leokris [45]

Answer:

a. 32.67 rad/s²  b. 29.4 m/s²

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a. The initial angular acceleration of the rod

Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.

So, Iα = WL

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dividing through by mL, we have

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multiplying both sides by 3, we have

Lα = 3g

dividing both sides by L, we have

α = 3g/L

Substituting the values of the variables, we have

α = 3g/L

= 3 × 9.8 m/s²/0.9 m

= 29.4/0.9 rad/s²

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b. The initial linear acceleration of the right end of the rod?

The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²

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Answer:

perpendicular to

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