All categories

2 years ago

A value that describes how heavy an object is and is related to the force of gravity is

Physics

2 answers:

Slav-nsk [51]2 years ago

6 0

The heaviness of an object with the relation to force of gravity, is described by the ‘weight’

<u>Explanation: </u>

The heaviness of the object is referred to the mass of the object. When the mass of the object is concerned it is taken in space or vacuum where force of gravity do not exist.

Therefore, to value the actual heaviness of the object, mass is multiplied by the component of force of gravity, is termed as weight.

$\bold{\text { Weight }=\text { Mass } \times \text { Accleration due to gravity }}$

Natasha_Volkova [10]2 years ago

3 0

Answer:

mass

Explanation:

You might be interested in

The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle

jasenka [17]

It depends what is the position of earth and saturn. Distance from earth to saturn varies depending on whether earth is between sun and saturn or sun is between earth and saturn. Obviously, the shortest distance will be if earth is between sun and saturn. we will take that the distance between earth and saturn is:

s = 1 275 000 000 km
The time required to travel that distance is:
t = s/v = 45535 hours or 1897.3 days

3 0

2 years ago

The position vector of a particle of mass 1.65 kg as a function of time is given by = (6.00 î + 4.15 t ĵ), where is in meters an

SashulF [63]

Answer:

L = 41.09 Kg m2 / s The angular momentum does not depend on the time

Explanation:

The definition of angular momentum is

L = r x p

Where blacks indicate vectors

Let's apply this definition our case. Linear momentum

p = m v

Let's replace

L = m r x v

The given function is

x = 6.00 i ^ + 4.15 t j ^

We look for speed

v = dx / dt

v = 0 + 4.15 j ^

To evaluate the angular momentum one of the best ways is to use determinants

$L = m \left[\begin{array}{ccc}i&j&k\\6&4.15t&0\\0&4.15&0\end{array}\right]$

L = m 6 4.15 k ^

The other products give zero

Let's calculate

L = 1.65 6 4.15 k ^

L = 41.09 Kg m2 / s

The angular momentum does not depend on the time

7 0

3 years ago

A 6.99-g bullet is moving horizontally with a velocity of +341 m/s, where the sign + indicates that it is moving to the right (s

Ratling [72]

Answer:

a). 1.218 m/s

b). R=2.8 $^{-3}$

Explanation:

$m_{bullet}=6.99g*\frac{1kg}{1000g}=6.99x10^{-3}kg$

$v_{bullet}=341\frac{m}{s}$

Momentum of the motion the first part of the motion have a momentum that is:

$P_{1}=m_{bullet}*v_{bullet}$

$P_{1}=6.99x10^{-3}kg*341\frac{m}{s} \\P_{1}=2.3529$

The final momentum is the motion before the action so:

a).

$P_{2}=m_{b1}*v_{fbullet}+(m_{b2}+m_{bullet})*v_{f}}$

$P_{2}=1.202 kg*0.554\frac{m}{s}+(1.523kg+6.99x10^{-3}kg)*v_{f}$

$P_{1}=P_{2}$

$2.529=0.665+(1.5299)*v_{f}\\v_{f}=\frac{1.864}{1.5299}\\v_{f}=1.218 \frac{m}{s}$

b).

kinetic energy

$K=\frac{1}{2}*m*(v)^{2}$

Kinetic energy after

$Ka=\frac{1}{2}*1.202*(0.554)^{2}+\frac{1}{2}*1.523*(1.218)^{2}\\Ka=1.142 J$

Kinetic energy before

$Kb=\frac{1}{2}*mb*(vf)^{2}\\Kb=\frac{1}{2}*6.99x10^{-3}kg*(341)^{2}\\Kb=406.4J$

Ratio = $\frac{Ka}{Kb}$

$R=\frac{1.14}{406.4}\\R=2.8x10^{-3}$

3 0

3 years ago

Figure 1 shows the motion of three balls. The curved paths followed by balls B and Care examples of

nlexa [21]

Answer:

in brainly app there is an option that you can upload graph, plot or diagram related to your question. you can use that app to show diagram related to your question so that one can answer your question in better way

7 0

2 years ago

What creates more pressure?

Evgesh-ka [11]

It is C, gasses with less kinetic energy, i did this and i think i remember it was C

8 0

2 years ago