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3 years ago

A value that describes how heavy an object is and is related to the force of gravity is

Physics

2 answers:

Slav-nsk [51]3 years ago

6 0

The heaviness of an object with the relation to force of gravity, is described by the ‘weight’

Explanation:

The heaviness of the object is referred to the mass of the object. When the mass of the object is concerned it is taken in space or vacuum where force of gravity do not exist.

Therefore, to value the actual heaviness of the object, mass is multiplied by the component of force of gravity, is termed as weight.

$\bold{\text { Weight }=\text { Mass } \times \text { Accleration due to gravity }}$

Natasha_Volkova [10]3 years ago

3 0

Answer:

mass

Explanation:

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If a body starts moving from rest its initial velocity is ų V zero m/s

Artist 52 [7]

Answer:

zero

When a Body start a from rest ,its initial velocity is zero.

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3 years ago

A building that is 105.50 ft. feet tall is casting a shadow that is 37.50 ft. feet. If the building next to it, is casting a sha

Arlecino [84]

115.35 ft

Set the proportion up 37.50/105.50 = 41/x and solve for x

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3 years ago

If you travel at 3 m/s for 12 seconds, how far did you travel?

ella [17]

Answer:

V=3 m/s

t=12 seconds

S=?

S=V×t

S=3×12

S=36meters

So distance you travel is 36meters.

4 0

3 years ago

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Starting from rest, a truck travels in a straight line for 8.0 s with a uniform acceleration of +1.6 m/s2. The driver then appli

lana [24]

Because it should be the total number

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4 years ago

If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth

fgiga [73]

Answer: The elevation in boiling point is 1.024°C.

Explanation:

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=ik_b\times m$

where,

i = Van't Hoff factor = 2 (for NaCl)

$\Delta T_b$ = change in boiling point = ?

$k_b$ = boiling point constant = $0.512^oC/m$

m = molality = 1.0 m

Putting values in above equation, we get:

$\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC$

Hence, the elevation in boiling point is 1.024°C.

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3 years ago