All categories

2 years ago

A value that describes how heavy an object is and is related to the force of gravity is

Physics

2 answers:

Slav-nsk [51]2 years ago

6 0

The heaviness of an object with the relation to force of gravity, is described by the ‘weight’

<u>Explanation: </u>

The heaviness of the object is referred to the mass of the object. When the mass of the object is concerned it is taken in space or vacuum where force of gravity do not exist.

Therefore, to value the actual heaviness of the object, mass is multiplied by the component of force of gravity, is termed as weight.

$\bold{\text { Weight }=\text { Mass } \times \text { Accleration due to gravity }}$

Natasha_Volkova [10]2 years ago

3 0

Answer:

mass

Explanation:

You might be interested in

Preston goes on a camel safari. There, he travels 5 km north, then 3 km east.

sammy [17]

7777Answer:

Explanation:

6 0

2 years ago

Read 2 more answers

How are waves that are created by a musical instrument and waves that

Wittaler [7]

Answer:

both caused by physical vibrations

7 0

3 years ago

A person just supports a mass of 20kg suspended from a rope.

Georgia [21]

Answer:

F = 200 N

Explanation:

Given that,

The mass suspended from the rope, m = 20 kg

We need to find the resultant force acting on the rope. The resultant force on the rope is equal to its weight such that,

F = mg

Where

g is acceleration due to gravity

Put all the values,

F = 20 kg × 10 m/s²

F = 200 N

So, the resultant force on the mass is 200 N.

7 0

2 years ago

The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum

kirill115 [55]

Answer:

The maximum voltage is 41.92 V.

Explanation:

Given that,

Peak voltage = 590 volts

Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is $1.20×10^{-2}\ \mu F$ .

We need to calculate the resonance frequency

Using formula of frequency

$f=\dfrac{1}{2\pi\sqrt{LC}}$

Put the value into the formula

$f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}$

$f=2356.88\ Hz$

We need to calculate the maximum current

Using formula of current

$I=\dfrac{V_{c}}{X_{c}}$

$I=2\pi\times f\times C\times V_{c}$

$I=2\pi\times2356.88\times1.20\times10^{-8}\times590$

$I=0.1048\ A$

Impedance of the circuit is

$z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}$

At resonance frequency $X_{L}=X_{C}$

$Z=R$

We need to calculate the maximum voltage

Using ohm's law

$V=I\times R$

$V=0.1048\times400$

$V=41.92\ V$

Hence, The maximum voltage is 41.92 V.

4 0

3 years ago

What is the electron configuration of this element? *for ne

Serhud [2]

Answer:

[He]2s²2p⁶

Explanation:

8 0

3 years ago

Read 2 more answers