Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m
Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²
Let v = speed of pumping the gasoline, m/s
Then the mass flow rate is
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s
The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s
Answer: 2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
Answer:
Explanation:
Given
Pipe is lowered to the water 
Negative Pressure is applied to raise the water
Pressure is given by

where 




(b)8.82 atm is much lower than the vapor pressure of water
(c)The fact of applying a negative pressure of 8.74 below the vapor pressure of water
Answer:
<u>The car's fast. The ground isn't moving.</u>
Hope this helped! :D
Answer:
27.5 days
0.92 month
Explanation:
= radius of the orbit of moon around the earth = 
= Mass of earth = 
= Time period of moon's motion
According to Kepler's third law, Time period is related to radius of orbit as

inserting the values, we get

we know that
1 day = 24 hours = 24 x 3600 sec = 86400 s

1 month = 30 days
