To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:
Indicates the intensity of the light before passing through the Polarizer,
I = The resulting intensity, and
= Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.
There is 3 polarizer, then
For the exit of the first polarizer we have that the intensity is,
For the third polarizer then we have,
Replacing with the first equation,
Therefore the transmitted intensity now is 
of the initial intensity.
You've described two (2) axes of motion.
The third one would have been up-and-down.
We can assume the process to be adiabatic such that we can make use of the formula:
W = R (T2 - T1) / (γ - 1)
W = 8.314 (297 - 17) / (1.4 - 1)
W = 700 J/mole
multiplying the number of moles
W = 700 (0.43)
W = 301 J
The work done is 301 J.
Answer:
Explanation:
The final velocity is given by the following kinematic equation:
Here, 
is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:
Now, we calculate the final velocity:
27.8 seconds is how long it would take to land
