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slega [8]
10 months ago
9

two masses 3 kg and 5 kg are connected by a string. a force of 20 n is applied to the 3 kg mass. what is the tension on the stri

ng and the acceleration of the mass.
Physics
1 answer:
atroni [7]10 months ago
5 0

The tension on the string = <u>12 N </u>and acceleration of the mass = <u>2.4 m/s² </u>of the two masses .

<h3>Tension of a string :</h3>

The tension of  a given strand of string or rope is a result of the forces pulling on the rope from other  end. As a reminder, force = mass × acceleration. Considering , the rope is stretched tightly, any change in acceleration or mass in objects the rope is supporting will cause a change in tension within the rope.

<h3>Evaluating the numerical :</h3>

m₁ = 3kg

m₂ =  5kg

F = 20 N Applied on 3 kg

F - T = m₁a

T = m₂a                        ( T = tension )

F - m₂a = m₁a                ( a = acceleration )

F = ( m₁ + m₂ )a

20 N = ( 3 kg + 5 kg )a

a = 2.4 m/s²

When F is applied on 3 kg block

      T = m₂a

       T = 5 × 2.4

T = 12 N

<h3>What is acceleration explain?</h3>

Acceleration, is defined as  rate at which velocity changes with time, in terms of both speed and direction. some extent or an object moving in a straight line is accelerated if it speeds up or slows down. Motion on a circle is accelerated whether or not the speed is constant, because the direction is continually changing

Learn more about Tension of a string :

brainly.com/question/24994188

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hjlf

Answer:

85.8 m/s

Explanation:

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where dθ/dt = ω = angular speed = v'/r where v' = maximum speed of plane and r = radius of circular path

Now, from θ = θ₀ + ωt where θ₀ = 0 rad, ω = angular speed  and t = time,

θ = θ₀ + ωt = 0 + ωt = ωt

So, v = rdθ/dt + θdr/dt

v = rω + ωtdr/dt

v = (r + tdr/dt)ω

v = (r + tdr/dt)v'/r

v = v' + tv'/r(dr/dt)

v = v'[1 + t(dr/dt)/r]

Given that v' = 110 m/s, t = 33.0s, r = 120 m and dr/dt = rate at which line is shortened = -0.80 m/s (negative since it is decreasing)

So, v = 110 m/s[1 + 33.0 s(-0.80 m/s)/120 m]

v = 110 m/s[1 + 11.0 s(-0.80 m/s)/40 m]

v = 110 m/s[1 + 11.0 s(-0.02/s)]

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8 0
2 years ago
) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th
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Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

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Now, we will substitute 0 for both z_{1} and z_{2}, 0 for w, 334.9 kJ/kg for h_{1}, 2726.5 kJ/kg for h_{2}, 5 m/s for V_{1} and 220 m/s for V_{2}.

Putting the given values into the above formula as follows.

     m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w  

     1 \times [334.9 \times 10^{3} J/kg + \frac{(5 m/s)^{2}}{2} + 0] + q = 1 \times [2726.5 \times 10^{3} + \frac{(220 m/s)^{2}}{2} + 0] + 0

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6 0
3 years ago
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IRINA_888 [86]

Answer:

A person that weighs 63.7 kg weighs 63.7 kg

Explanation:

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=10√183
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3 years ago
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