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Inessa [10]
3 years ago
10

1. Surface area, agitation, and ____ affect the dissolving rate of a solid. 1. termperature 2. location​

Chemistry
2 answers:
Fiesta28 [93]3 years ago
4 0
I don’t understand???
mamaluj [8]3 years ago
3 0

Answer:??

Explanation:

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Can you store cuso4 in an aluminum container? explain your reasoning
mash [69]

We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.

<h3>Can you store cuso4 in an aluminum container?</h3>

Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.

So we can store the copper sulphate solution in alumiun container.

Learn more about container here: brainly.com/question/11459708

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2 years ago
Who is good at CHEMISTRY?????????/I NEED HELP
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With what?

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Which statement best describes the properties of sucrose?
crimeas [40]

Answer:

D. They are different from the properties of carbon, oxygen, and hydrogen.  

Step-by-step explanation:

Carbon, oxygen, and hydrogen are all <em>elements. </em>

Sucrose is a <em>compound</em> containing carbon, oxygen, and hydrogen. Its properties are different from those of its elements.

For example, carbon is a <em>black solid,</em> while oxygen and hydrogen are <em>colourless gases</em>. Sucrose is a <em>white solid</em>.

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3 years ago
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To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Elis [28]

<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

Hence, the number of moles of weak acid is 4.24\times 10^{-3} moles.

6 0
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