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3 years ago

What is the acceleration of a 4.5 kg mass pushed by a 15n force? ANSWER ASAP PLEASE

Physics

1 answer:

nikitadnepr [17]3 years ago

3 0

Answer: 3.33 m/s²

Explanation:

F = (m)(a)

15 N = (4.5 kg)(a)

15/4.9 = 3.33

a = 3.33 m/s²

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The distance between the earth and sun is 1.5 x 108 kilometers and the speed of light is 3.00 x 108 meters per second. Calculate

butalik [34]

Answer:

time = 8.3333 minutes.

Explanation:

distance between earth and sun = 1.5 * $10^{8}km$

speed of light = 3* $10^{8}m/s$

convert the distance unit from km to m so we can have uniform units.

distance between earth and sun = 1.5 * $10^{8}*1000$ m

distance between earth and sun = 1.5 * $10^{11}$ m

speed = distance /time

time = distance / speed

time = $\frac{1.5*10^{11} }{3*10^{8} }$

$= 0.5*10^{3}$

time =500 sec

time = 500/60 minutes

time = 8.3333 minutes.

3 0

2 years ago

What is the specific heat for the aluminum wire?

Alisiya [41]

0.902

hope this helps :)

4 0

2 years ago

A hydrogen atom has a diameter of about 12.7 nm, express this diameter in centimeters.

Andrej [43]

1 meter = 1e9 nm
To get meters, divide nanometers by 1e9: 9.95nm / 1x10^9 = 9.95x10^-9 meters
Answer: 9.95e-9 meters

3 0

2 years ago

Read 2 more answers

How do resistors in parallel affect the total resistance?

4vir4ik [10]

Answer:

They're going to increase the total resistance as $R_{T} = \sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}$

Explanation:

If the resistors are in parallel, the potential difference is the same for each resistor. But the total current is the sum of the currents that pass through each of the resistors. Then

$I = I_1 + I_2 + ... + I_N$

where

$I_i = \frac{V_i}{R_i}$

but

$V_i = V_j = V$ for $i,j= 1, 2,..., N$

$I = \frac{V}{R_1}+ \frac{V}{R_2} + ... + \frac{V}{R_N} = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)V = \frac{V}{R_T}$

where

$R_T = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)^{-1} =\sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}$

4 0

2 years ago

A 150 kg boy and his bike are traveling 12 m/s when he slams on his breaks and stop at his friend’s house. How much impulse is r

Nataly [62]

Answer:

J = 1800 kg-m/s

Explanation:

Given that,

Mass of a boy, m = 150 kg

Initial velocity of a boy, u = 12 m/s

Finally, it stops, v = 0

We need to find the impulse is required to produce this change in momentum. We know that impulse is equal to the change in momentum. So,

$J=m(v-u)\\\\=150\times (0-12)\\\\=-1800\ kg-m/s\\\\|J|=1800\ kg-m/s$

So, the impulse is equal to 1800 kg-m/s

4 0

3 years ago