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GalinKa [24]
2 years ago
7

PLEASE HELP THIS IS DUE LIKE HELP ME PLEASE

Physics
1 answer:
marysya [2.9K]2 years ago
5 0

Answer:

At the end points of motion (either side) the velocity must be zero because the velocity is changing from - to + (it can't turn around around without passing thru zero,

The velocity will then increase to the midpoint of the motion.

m g h = 1/2 m v^2    where h is the vertical distance thru which the pendulum travels

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How much heat is required to convert 5.53 g of ice at -12.0 ∘C to water at 24.0 ∘C? (The heat capacity of ice is 2.09 J/(g⋅∘C),
fredd [130]

Answer:

2.55 × 10³ J =2.55 kJ

Explanation:

Specific heat capacity of ice =  37.8 J / mol °C

Specific heat capacity of water = 76.0 J/ mol °C

Ice at -12 °C is converted to ice at 0 °C by absorbing heat Q₁

Ice at 0°C melts to water at 0 °C. Let Heat  absorbed during this phase change be Q₂ .

Let heat  absorbed to raise the temperature of water from 0 C to 24°C be Q₃ .

Total heat = Q = Q₁ + Q₂ + Q₃

Q₁ = (37.8 j/mol C )(5.53 g /18.01532 g/ mol )( 0-(-12)) = 139.23749 j

Q₂ =(5.53 g/18.01532 g H₂O / mol ) (6.02 x10³ j) = 1847.905 j

Q₃ = (76 j/mol C) ( (5.53 g/18.01532 g H₂O / mol )(24-0) = 559.8968 j

Total Heat required = Q = 139.23749 j + 1847.905 j + 559.8968 j

= 2547.039 j = 2.55 × 10³ J =2.55 kJ

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4 years ago
Name the 2 types of tissue that form your skin?
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Epithelial tissue and Muscle tissue

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A wave has a wavelength of 5 meters and a frequency of 3 hertz. What is the speed of the wave?
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4 years ago
What distance does light travel in water, glass, and diamond during the time that it travels 1.0 m in vacuum? The refractive ind
lidiya [134]

Answer:

refractive index for water,glass,diamond are 0.752m, 0.667m, 0.413m respectively

Explanation:

refractive index (n) = \frac{velocity of light in air/vacuum}{velocity of light in substance}

velocity =\frac{distance}{time}

The time for travel is kept constant for all mediums.

refractive index (n) = \frac{\frac{distance in vacuum}{time} }{\frac{distance in medium}{time} }\\ \\=\frac{distance in vacuum}{distance in medium}

distance in medium = \frac{distance in vacuum}{refractive index of medium}

S_{medium}  = \frac{S_{vacuum} }{n_{medium} }

For water, n= 1.33

S_{water} = \frac{1 }{1.33}

S_{water} = 0.752m

For glass, n=1.5

S_{glass}= \frac{1 }{1.5}

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For diamond, n= 2.42

S_{diamond} = \frac{1 }{2.42}

S_{diamond} = 0.413m

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3 years ago
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