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GalinKa [24]
3 years ago
7

PLEASE HELP THIS IS DUE LIKE HELP ME PLEASE

Physics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer:

At the end points of motion (either side) the velocity must be zero because the velocity is changing from - to + (it can't turn around around without passing thru zero,

The velocity will then increase to the midpoint of the motion.

m g h = 1/2 m v^2    where h is the vertical distance thru which the pendulum travels

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We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3
GalinKa [24]
we would be at (4,0)
7 0
3 years ago
The Grinch is trying to push a 5000-kg sled up the side of Mount Crumpit (whose side make an angle of 60 degrees above the horiz
navik [9.2K]

Answer:

Explanation:

height lost h  = 300 sin60

= 259.8 m .

gravitational potential energy = mgh

= 5000 x 9.8 x 259.8

= 1273 x 10⁴ J

Kinetic energy

=  1/2 mv²

= .5 x 5000 x 60²

= 900 x 10⁴ J

there is loss of kinetic energy = 373 x 10⁴ J.

This loss in energy is due to kinetic friction that came into action when the sled slipped downwards.

The lost energy is converted into heat energy or thermal energy.

8 0
4 years ago
A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.
dsp73

Answer:

<h3>0.445</h3>

Explanation:

In friction, the coefficient of friction formula is expressed as;

\mu = \frac{F_f}{R}

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta

Given

θ = 24°

\mu = tan 24^0\\\mu = 0.445\\

Hence the coefficient of kinetic friction between the box and the ramp is 0.445

3 0
3 years ago
When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rat
svlad2 [7]

Answer:

343/1500

Explanation:

Power: This can be defined as the product force and velocity. The S.I unit of power is Watt (w).

From the question,

P' = mg×v................. Equation 1

Where P' = power used to gain an altitude, m = mass of the engine, g = acceleration due to gravity of the engine, v = velocity of the engine.

Given: m = 700 kg, v = 2.5 m/s, g = 9.8 m/s²

Substitute into equation 1

P' = 700(2.5)(9.8)

P' = 17150 W.

If the full power generated by the engine = 75000 W

The fraction of the engine power used to make the climb = 17150/75000

= 343/1500

8 0
3 years ago
The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength
Archy [21]

The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

Learn more here:brainly.com/question/21431500

4 0
3 years ago
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