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zhannawk [14.2K]
3 years ago
14

The horizontal surface on which the objects slide is frictionless. If M = 1.0 kg and the magnitude of the force of the small blo

ck on the large block is 5.2 N, determine F
---->2M4M
Physics
1 answer:
sweet-ann [11.9K]3 years ago
5 0

Answer:

The force is 7.8 N.

Explanation:

Given that,

Mass of small object = 2M

Mass of large object = 4M

Here, M = 1.0 kg

Force of the small block = 5.2 N

We need to calculate the acceleration of 4 kg block

Using formula of force

F=ma

a=\dfrac{F}{m}

a=\dfrac{5.2}{4}

a=1.3\ m/s^2

The 2 kg block is also accelerating at 1.3 m/s², making a total of 6 kg.

We need to calculate the force

Using formula of force

F=ma

Put the value into the formula

F=6\times1.3

F=7.8\ N

Hence, The force is 7.8 N.

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Read 2 more answers
A transverse wave on a long horizontal rope with a
frosja888 [35]

Answer:

2 seconds

Explanation:

The frequency of a wave is related to its wavelength and  speed by the equation

f=\frac{v}{\lambda}

where

f is the frequency

v is the speed of the wave

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For the wave in this problem,

v = 2 m/s

\lambda=8 m

So the frequency is

f=\frac{2}{8}=0.25 Hz

The period of a wave is equal to the reciprocal of the frequency, so for this wave:

T=\frac{1}{f}=\frac{1}{0.25}=4 s

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Therefore, the time taken for the wave to go from a point with displacement +A to a point with displacement -A is half the period, therefore for this wave:

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2 years ago
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