The new gravitational attraction will be 1/4 as much
Explanation:
The magnitude of the gravitational force between two objects is given by
where
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them
In this problem, the original force between the two objects is F, when they are separated by a distance r.
Later, the distance between the two objects is doubled, so the new distance is
![r'=2r](https://tex.z-dn.net/?f=r%27%3D2r)
Therefore, the new force will be
![F'=G\frac{m_1 m_2}{(2r)^2}=\frac{1}{4}(\frac{Gm_1 m_2}{r^2})=\frac{F}{4}](https://tex.z-dn.net/?f=F%27%3DG%5Cfrac%7Bm_1%20m_2%7D%7B%282r%29%5E2%7D%3D%5Cfrac%7B1%7D%7B4%7D%28%5Cfrac%7BGm_1%20m_2%7D%7Br%5E2%7D%29%3D%5Cfrac%7BF%7D%7B4%7D)
Therefore, the new force will be one-fourth as much.
Learn more about gravitational force:
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It will be 3 wavelengths because 1 cycle = 1 wavelength.
Answer:
3.15m³
Explanation:
To solve this problem, let us first find the mass of the petrol from the given dimension.
Mass = density x volume
Volume of petrol = 4.2m³
Density of petrol = 0.3kgm⁻³
Mass of petrol = 4.2 x 0.3 = 1.26kg
So;
We can now find the volume of the alcohol
Volume of alcohol =
Mass of alcohol = 1.26kg
Density of alcohol = 0.4kgm⁻³
Volume of alcohol =
= 3.15m³