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zhannawk [14.2K]
3 years ago
14

The horizontal surface on which the objects slide is frictionless. If M = 1.0 kg and the magnitude of the force of the small blo

ck on the large block is 5.2 N, determine F
---->2M4M
Physics
1 answer:
sweet-ann [11.9K]3 years ago
5 0

Answer:

The force is 7.8 N.

Explanation:

Given that,

Mass of small object = 2M

Mass of large object = 4M

Here, M = 1.0 kg

Force of the small block = 5.2 N

We need to calculate the acceleration of 4 kg block

Using formula of force

F=ma

a=\dfrac{F}{m}

a=\dfrac{5.2}{4}

a=1.3\ m/s^2

The 2 kg block is also accelerating at 1.3 m/s², making a total of 6 kg.

We need to calculate the force

Using formula of force

F=ma

Put the value into the formula

F=6\times1.3

F=7.8\ N

Hence, The force is 7.8 N.

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jenyasd209 [6]

Answer:

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Explanation:

4 0
3 years ago
Froghopper insects have a typical mass of around 11.3 mg and can jump to a height of 58.8 cm. The takeoff velocity is achieved a
allochka39001 [22]

Answer:

2874.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{v^2-0^2}{2\times h}\\\Rightarrow v^2=2ah\ m/s

Now H-h = 0.588 - 0.002 = 0.586 m

The final velocity will be the initial velocity

v^2-u^2=2as\\\Rightarrow 0^2-u^2=2gs\\\Rightarrow -2ah=2\times g(H-h)\\\Rightarrow -2a0.002=2\times g0.586\\\Rightarrow a=-\frac{0.586\times -9.81}{0.002}\\\Rightarrow a=2874.33\ m/s^2

Acceleration of the frog is 2874.33 m/s²

6 0
3 years ago
Find the sum 5.24 g, 43.261 g, and 7.3458 g. Write your answer with the correct amount of significant figures.
lapo4ka [179]

Answer:

This is how I do it:

  • 5.24 rounded to one significant figure is 5
  • 43.261 rounded to one significant figure is 40.
  • 7.3458 rounded to one significant figure is 7.
  • 5 + 40 + 7 is 52 g

Hope this helps you.

Explanation:

7 0
3 years ago
Stars of spectral type A and F are considered ________.
LekaFEV [45]

Answer:

<u>B. the stars of spectral type A and F are considered reasonably to have habitable planets but much less likely to have planets with complex plant - or animal - like life.</u>

Explanation:

The appropriate spectral range for habitable stars is considered to be "late F" or "G", to "mid-K" or even late "A". <em>This corresponds to temperatures of a little more than 7,000 K down to a little less than 4,000 K</em> (6,700 °C to 3,700 °C); the Sun, a G2 star at 5,777 K, is well within these bounds. "Middle-class" stars (late A, late F, G , mid K )of this sort have a number of characteristics considered important to planetary habitability:

• They live at least a few billion years, allowing life a chance to evolve. <em>More luminous main-sequence stars of the "O", "B", and "A" classes usually live less than a billion years and in exceptional cases less than 10 million.</em>

• They emit enough high-frequency ultraviolet radiation to trigger important atmospheric dynamics such as ozone formation, but not so much that ionisation destroys incipient life.

• They emit sufficient radiation at wavelengths conducive to photosynthesis.

• Liquid water may exist on the surface of planets orbiting them at a distance that does not induce tidal locking.

<u><em>Thus , the stars of spectral type A and F are considered reasonably to have habitable planets but much less likely to have planets with complex plant - or animak - like life.</em></u>

4 0
3 years ago
What is potential difference also called?
malfutka [58]
Voltage - V = IR : v= voltage i= current r= resistance
6 0
3 years ago
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