The horizontal surface on which the objects slide is frictionless. If M = 1.0 kg and the magnitude of the force of the small blo
1 answer:
Answer:
The force is 7.8 N.
Explanation:
Given that,
Mass of small object = 2M
Mass of large object = 4M
Here, M = 1.0 kg
Force of the small block = 5.2 N
We need to calculate the acceleration of 4 kg block
Using formula of force
The 2 kg block is also accelerating at 1.3 m/s², making a total of 6 kg.
We need to calculate the force
Using formula of force
Put the value into the formula
Hence, The force is 7.8 N.
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Answer:
d = 0.38 m
Explanation:
As we know that the person due to the airbag action, comes to a complete stop, in 36 msec or less, and during this time, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:
vf = v₀ -a*t
If vf = 0, we can solve for v₀:
v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s
With the values of v₀, a and t, we can find Δx, applying any kinematic equation that relates all of some of these parameters with the displacement.
Just for simplicity, we can use the following equation:
where vf=0, v₀ =21.2 m/s and a= -588 m/s².
Solving for d:
⇒ d = 0.38 m
Answer:
the maximum height reached by the marble is 11.84 m.
Explanation:
Given;
mass of the marble, m = 0.02 kg
extension of the string, x = 0.08 m
force applied to the string, F = 58 N
Apply the principle of conservation of energy;
elastic potential energy = gravitational potential energy
¹/₂fx = mgh
Therefore, the maximum height reached by the marble is 11.84 m.