Answer:
it’s the third option: 4,600,000 km
Explanation:
just took the test and that was correct
Answer:
The acceleration of the car is 5m/s²
Explanation:
Given data
Force F= 4,000N
Mass of car m= 800kg
Acceleration a= ?
Applying the Newton's second law of motion which states that the rate of change of momentum of a body is proportional to the external force and takes place in the direction of the force
F=ma
a= F/m
a= 4000/800
a=5m/s²
<span><span><span>FIRST EQUATION OF MOTION
Vf = Vi + at</span> </span><span>Consider a body initial moving with velocity "Vi". After a certain interval of time "t", its velocity becomes "Vf". Now</span>Change in velocity = Vf - Vi <span>
OR
DV =Vf – Vi</span><span>Due to change in velocity, an acceleration "A" is produced in the body. Acceleration is given by</span>a = DV/t Putting the value of "DV"<span><span>a = (Vf – Vi)/t
at = Vf – Vi
at + Vi =Vf
</span>OR
</span><span>Vf = Vi + at
</span>
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Answer:
the action of measuring something.
Answer:
(a) 388 newton
(b) 17.15 m/s
Explanation:
r = 30 m
v = 10 m/s
m = 60 kg
(a) Let N be the normal reaction.
At the bump
N = mg - mv^2 / r
N = 60 x 9.8 - 60 x 10 x 10 / 30 = 588 - 200 = 388 newton
(b) Then the contact loose, N = 0
So, mg = mv^2 / r
v^2 = r x g = 30 x 9.8 = 294
v = 17.15 m/s