Answer:
86 turns
Explanation:
Parameters given:
Magnetic torque, τ = 1.7 * 10^(-2) Nm
Area of coil, A = 9 * 10^(-4) m²
Current in coil, I = 1.1 A
Magnetic field, B = 0.2 T
The magnetic toque is given mathematically as:
τ = N * I * A * B
Where N = number of turns
To find the number of turns, we make N subject of formula:
N = τ/(I * A * B)
Therefore:
N = (1.7 * 10^(-2)) / (1.1 * 9 * 10^(-4) * 0.2)
N = 85.85 = 86 turns (whole number)
The number of turns must be 86.
Answer:
besides a reduction in friction, the only way to increase the amount of work output of a machine is to Increase the work input
i
Explanation:
The correct option is (B) <span>Aluminum is a metal and is shiny, malleable, ductile, conducts heat and electricity, forms basic oxides, and forms cations in aqueous solution.
Since Aluminium is in group 13, and all the elements in group 13 are either metals or metalloids(Boron). Hence we are left with option (B) and (D). Boron is the only metalloid in group 13 and aluminium is a metal(not a metalloid); therefore, we are left with only one option which is Option (B). And Aluminium is </span>shiny, malleable, ductile, conducts heat and electricity, forms basic oxides, and forms cations in aqueous solution.<span>
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Yes.....The continetal plates shifting would cause either disaster...
