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ale4655 [162]
3 years ago
10

A parcel of air is being forced up the windward side of a 7,000-foot-high mountain. The parcel has a temperature of 91.0°F at 0

feet in elevation. If the LCL is located at 5,000 feet, what is the temperature of this parcel of air at 1,000 feet?
Physics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

Temperature of parcel at 1000 ft is 85.5°F

Explanation:

Temperature of parcel at 0 ft =T₁ = 91.0°F

Dry adiabatic rate = 5.5°F/100 ft

Temperature of parcel at H₂ (1000 ft) = T₂ =?

Height of LCL = 5000 ft

As (1000<5000), so using the formula for parcel below or at the LCL i.e.

                        T_{2}=T_{1}-\Delta T

                        \Delta T =H_{2}\times DAR

                        \Delta T=1000(\frac{5.5}{1000})

                        \Delta T= 5.5^{o}

                        T_{2}=91.0-5.5

                        T_{2}=85.5^{o}F

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A car is traveling at a velocity of 22 m/s when the driver puts on the brakes
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The car’s velocity at the end of this distance is <em>18.17 m/s.</em>

Given the following data:

  • Initial velocity, U = 22 m/s
  • Deceleration, d = 1.4 m/s^2
  • Distance, S = 110 meters

To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

V^2 = U^2 + 2dS

Substituting the values into the formula, we have;

V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}

<em>Final velocity, V = 18.17 m/s</em>

Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>

<em></em>

Read more: brainly.com/question/8898885

8 0
2 years ago
A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
KIM [24]

Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately.

8 0
2 years ago
You connected the 5 Ω, 10 Ω, 15 Ω resistors in series with a 90 V battery. What is the current?​
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Answer:

3A

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What is the direction of the force on a positive charge when passing through a magnetic field as indicated in this diagram? Expl
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Answer:

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hope this helps

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