Answer:
33.61°
Explanation:
Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.
Or ,
n = c/v.
v is the velocity in the medium (2.3 × 10⁸ m/s)
c is the speed of light in air = 3.0 × 10⁸ m/s
So,
n = 3.0 × 10⁸ / 2.3 × 10⁸
n = 1.31
Using Snell's law as:
Where,
is the angle of incidence ( 25.0° )
is the angle of refraction ( ? )
is the refractive index of the refraction medium (air, n=1)
is the refractive index of the incidence medium (glass, n=1.31)
Hence,
Angle of refraction = 
= 33.61°
Answer:
a) 
= 692 N
b) 
= 932 N
Explanation:
a)
According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object in all directions.
∝ a
= ma
= ma
Given data:
= 800 N
Mass = m = 90 kg
acceleration = a = 1.2 m/s²
= ?
800 - = (90)(1.2)
= 692 N
b)
According to newton's second law of motion,
∝ a
= ma
= ma
Given data:
If we assume the same friction and acceleration between player's feet and ground as calculated in part a
= 692 N
acceleration = a = 1.2 m/s²
We take the equal mass to the total mass of both the players because when the winning player push losing player backward, he exert force on the ground not only due to his mass but also due to the mass of losing player.
Mass = M = m₁ + m₂ = 110 kg + 90 kg
= 200 kg
= ?
- 692 N = (200)(1.2)
= 692 + 240
= 932 N
Answer:Physics. Distance, the total distance an object travels dependent on its path through space. Optical path length, the product of the distance light travels and the refractive index of the medium it travels through. Mean free path, the average distance that a particle travels before scattering.
Explanation:
Answer:
C.
m
Explanation:
We are given that
Weight of board=w=10 N
Length of board=L=5 m
Tension in the string=T=3 N
Applied upward force=F=7 N
We have to find the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.
Let r be the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.
The board is uniform therefore, the center of board is the mid- point of board.
Therefore, the lever arm of weight=
Now, the torque exerted by the weight of the board
The torque exerted by applied force=
In static equilibrium
The sum of rotational forces=0
The two rotational force act in opposite direction therefore,
Substitute the values
m
Hence, option C is true.
The moon is moving away from Earth at a rate of approximately 3.78 cm per year.
This migration of the Moon from the Earth is mainly due to the action of the Earth tides. It can be explained as follows:
- the Moon exerts a gravitational force on the Earth, which is stronger at the Equator (since the Equator is closer to the Moon), creating the tides
- However, the Earth rotates faster on its axis (one rotation every 24 hours) than the Moon (one rotation every 27 days), therefore the tidal bulge on Earth tries to pull the Moon "ahead" in its orbit. As a result, the Moon tends to sped up.
<span>- As opposite reaction, the Earth tends to slow down in its rotation, with a loss of angular momentum. Since the angular momentum must be conserved, the radius of the orbit of the Moon becomes larger, and this explains why the Moon is moving away from the Earth.</span>
