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ale4655 [162]
3 years ago
10

A parcel of air is being forced up the windward side of a 7,000-foot-high mountain. The parcel has a temperature of 91.0°F at 0

feet in elevation. If the LCL is located at 5,000 feet, what is the temperature of this parcel of air at 1,000 feet?
Physics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

Temperature of parcel at 1000 ft is 85.5°F

Explanation:

Temperature of parcel at 0 ft =T₁ = 91.0°F

Dry adiabatic rate = 5.5°F/100 ft

Temperature of parcel at H₂ (1000 ft) = T₂ =?

Height of LCL = 5000 ft

As (1000<5000), so using the formula for parcel below or at the LCL i.e.

                        T_{2}=T_{1}-\Delta T

                        \Delta T =H_{2}\times DAR

                        \Delta T=1000(\frac{5.5}{1000})

                        \Delta T= 5.5^{o}

                        T_{2}=91.0-5.5

                        T_{2}=85.5^{o}F

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irga5000 [103]

Answer:

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Explanation:

The given mass of the ball, m = 86 g = 0.089 kg

The height from which the ball is dropped, H = 2.87 m

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Mathematically, we have;

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Where;

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Δt = The time of contact with the force

The velocity of the ball just before it touches the ground, v₁ = -√(2·g·H)

The velocity with which the ball leaves, v₂ = √(2·g·h)

The change in momentum, Δp = m·(v₂ - v₁)

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The impulse, Δp, received by the ball from the floor during the bounce is given as follows;

Δp = 0.089 kg × (√(2 × 9.8 m/s² × 1.28 m) + √(2 × 9.8 m/s² × 2.87 m)) ≈ 1.11329438 m·kg/s

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