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2 years ago

If a car can accelerate from rest to 45 mph in 6 seconds, what is the car's

Physics

1 answer:

sukhopar [10]2 years ago

3 0

Answer:

Lets see this

Explanation:

So workout the mph of an average car then try and find out the speed

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A circular loop of wire with a radius of 20 cm lies in the xy plane and carries a current of 2 A, counterclockwise when viewed f

Zina [86]

To solve this problem we will apply the concept related to the magnetic dipole moment that is defined as the product between the current and the object area. In our case we have the radius so we will get the area, which would be

$A=\pi r^2$

$A =\pi (0.2)^2$

$A =0.1256 m^2$

Once the area is obtained, it is possible to calculate the magnetic dipole moment considering the previously given definition:

$\mu=IA$

$\mu=2(0.1256)$

$\mu=0.25 A\cdot m^2$

Therefore the magnetic dipole moment is $0.25A\cdot m^2$

6 0

3 years ago

How do you cram for a sicence test

Slav-nsk [51]

Best way that I study is first get in a comfortable room. Get the material you are suppose to be studying and a blank note book. Go through what you think you know then take what you struggle with a write it in the notebook. After writing it a few times different ways find what helps you rember it the most.

7 0

3 years ago

Read 2 more answers

An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 17601760 × 103 seconds (ab

Yuliya22 [10]

Answer:

The value is $a_r = 3.81 *10^{-3} m/s^2$

Explanation:

Generally the moon's radial acceleration is mathematically represented as

$a_r = r * w^2$

Here $w$ is the angular velocity which is mathematically represented as

$w =\frac{2 \pi }{ T}$

substituting $1760 * 10^3 \ seconds$ for T(i.e the period of the moon ) we have

$w =\frac{2 * 3.142 }{ 1760 * 10^3}$

=> $w = 3.57 *10^{-6} \ rad/s$

From the question r(which is the radius of the orbit ) is evaluated as

$r = R + H$

substitute $3.60 * 10^6 m$ for R and $295.0 * 10^6 \ m$ H

$r = 295.0 * 10^6 +3.60 * 10^6$

=> $r = 2.986 *10^{8} \ m$

$a_r = 2.986 *10^{8} * ( 3.57 *10^{-6} )^2$

$a_r = 3.81 *10^{-3} m/s^2$

4 0

3 years ago

What it means to say that energy is conserved as a ball fall towards ground

stiv31 [10]

Mechanical energy = Potential Energy + Kinetic Energy

if there is no friction, M.E. is conserved
as a ball falls, it is losing height. (P.E.=mgh , therefore P.E. will decrease)

the potential energy is transformed into kinetic energy which equals 1/2MV^2.

the increase in K.E. equals the decrease in P.E.

and the sum of both equals M.E.

thus mechanical energy is conserved.

hope this helps you.

5 0

3 years ago

A student reads that nanosilver particles are used in cosmetics to allow nutrients to penetrate deeper into the skin. When the c

Vsevolod [243]

Answer: When the concentration of nanosilver particles in water is increased, the population of Daphnia magna will decrease

Explanation:

The statement below that is the most likely testable hypothesis based on the information provided is that when there is an increase in the concentration of nanosilver particles in water, the population of Daphnia magna will decrease.

Since we are informed that the particles may decrease survival in many aquatic organisms, it simply means that an increase in the particles in water will bring about the decrease in the Daphnia magna, which is the tiny freshwater crustacean.

7 0

3 years ago