Look at the chemical equation below.

AURORKA [14]

Taking into account the Newton's second law, the correct answer is option A. F = 9.68 N right

In first place, acceleration in a body occurs when a force acts on a body.

Newton's second law states that a force will change the speed of an object because the speed and/or direction will change. These changes in velocity are called acceleration.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object

Mathematically, Newton's second law is expressed as:

F= m×a

where:

F = Force [N]
m = Mass [kg]
a = Acceleration [m/s²]

In this case, you know:

F= ?
m= 2.2 kg
a= 4.4 m/s²

Replacing in Newton's second law:

F= 2.2 kg× 4.4 m/s²

Solving:

F= 9.68 N

Finally, As the bowl of fruit accelerates to the right, the correct answer is option A. F = 9.68 N right

Learn more about the Newton's second law:

brainly.com/question/23845187?referrer=searchResults

brainly.com/question/13959891?referrer=searchResults

6 0

2 years ago

There are no negative consequences to using nuclear energy. true or false

Travka [436]

False..........
it has so many consequences

7 0

3 years ago

Read 2 more answers

When the concentrations of CH 3 Br and NaOH are both 0.100 M, the rate of the reaction is 0.0030 M/s. What is the rate of the re

mash [69]

Answer : The rate of the reaction if the concentration of $CH_3Br$ is doubled is, 0.006 M/s

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The balanced equations will be:

$CH_3Br+NaOH\rightarrow CH_3OH+NaBr$

In this reaction, $CH_3Br$ and $NaOH$ are the reactants.

The rate law expression for the reaction is:

$\text{Rate}=k[CH_3Br][NaOH]$

As we are given that:

$[CH_3Br]$ = concentration of $CH_3Br$ = 0.100 M

$[NaOH]$ = concentration of $NaOH$ = 0.100 M

Rate = 0.0030 M/s

Now put all the given values in the above expression, we get:

$0.0030M/s=k\times (0.100M)\times (0.100M)$

$k=0.3M^{-1}s^{-1}$

Now we have to calculate the rate of the reaction if the concentration of $CH_3Br$ is doubled.

$\text{Rate}=k[CH_3Br][NaOH]$

$\text{Rate}=(0.3M^{-1}s^{-1})\times (2\times 0.100M)\times (0.100M)$

$\text{Rate}=0.006M/s$

Thus, the rate of the reaction if the concentration of $CH_3Br$ is doubled is, 0.006 M/s

3 0

4 years ago

Complete the blank with the correct answer choice. 3 meters = ________ millimeters A. 30 B. 300 C. 3,000 D. 30,000

Nata [24]

Answer : C.

3 meters=3000 millimeters

8 0

3 years ago

Ocean currents bring warm water from the _______ and cold water from the __________ *

AleksAgata [21]

Answer:

Ocean currents bring warm water from the equator and cold water from the poles *

Explanation:

More sun shines on the water near the equator than the water near the poles because of earth's axis. So warmer water comes from the equator and colder water comes from the poles.

6 0

4 years ago