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2 years ago

An unknown gas diffuses 1.25 times faster than CO2 gas. What is the molar mass of the unknown gas?

Chemistry

1 answer:

hodyreva [135]2 years ago

4 0

Answer:

28.16 g/mol

Explanation:

From Graham's law;

Let the rate of diffusion of gas X be 1.25

Let the rate of diffusion of CO2 be 1

Molecular mass of gas X= M

Molecular mass of CO2 = 44g/mol

1.25/1=√44/M

(1.25/1)^2 = 44/M

1.5625 = 44/M

M= 44/1.5625

M= 28.16 g/mol

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2 years ago

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Consider the neutralization reaction 2 HNO 3 ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + Ba ( NO 3 ) 2 ( aq ) A 0.120 L sample

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Explanation:

Step 1: Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

Step 2: The balanced equation

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Step 3: Calculate moles Ba(OH)2

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molarity = 0.01804 / 0.120 L

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2 years ago

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Answer:

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An unknown gas diffuses 1.25 times faster than CO2 gas. What is the molar mass of the unknown gas?​

An unknown gas diffuses 1.25 times faster than CO2 gas. What is the molar mass of the unknown gas?