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vlabodo [156]
3 years ago
9

What is the basic definition of carbohydrates

Chemistry
2 answers:
ikadub [295]3 years ago
8 0

Carbohydrates are substances that are found in foods such as bread and pasta, which provide the body with heat and energy. Chemically, carbohydrates are made of three kinds of elements namely carbon , hydrogen and oxygen.

Carbohydrates are separated into two main categories, simple carbohydrates and complex carbohydrates.  

Simple carbohydrates are those that contain one or two sugar molecules linked together. Complex carbohydrates are those that contain  three or more sugar molecules linked together. In some cases these chains can contain hundreds of sugar molecules. 

 

tatyana61 [14]3 years ago
4 0
Neutral compounds of carbon, hydrogen and oxygen
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What is the molar solubility of nickel(II) sulfide in 0.091 M KCN? For NiS, Ksp = 3.0 × 10 –19; for Ni(CN) 4 2–, Kf = 1.0 × 10 3
Marta_Voda [28]

Answer:

The value is  x =  0.0227  \  M

Explanation:

From the question we are told that

     The concentration of KCN \ \ i.e \ \ CN^{-} is  M_1 = 0.091 \  M

     The solubility product constant for NiS is  K_{sp} =  3.0 *10^{-19}

     The stability  constant for Ni(CN)_4 ^{2-} is  K_f =  1.0 *10^{31}

Generally the dissociation  reaction for NiS is  

       Ni S  \underset{}{\stackrel{}{\rightleftharpoons}}   Ni^{2+} + S^{2-}

Generally the formation reaction for Ni(CN)_4 ^{2-}   is  

      4CN^-  + N_i ^{2+}  \underset{}{\stackrel{}{\rightleftharpoons}}  \ Ni(CN)^{2-}_{4}

Combining both reaction we have

      4CN^ -  + NiS  \  \underset{}{\stackrel{}{\rightleftharpoons}} \   Ni(CN)^{2-}_4 + S^{2-}

Gnerally the equilibrium constant for this reaction is  

         K_c  =  K_{sp} * K_f

=>       K_c  = 3.0 *10^{-19 } * 1.0 *10^{31}  

=>       K_c  = 3.0*10^{12}

Generally the I C E  table for the above reaction is  

                     4CN^ -  \ \ \  + \ \ \ NiS  \ \ \ \ \ \ \  \underset{}{\stackrel{}{\rightleftharpoons}} \ \ \ \ \    Ni(CN)^{2-}_4 \ \ \ \ \ \ \ \ \ + \ \ \ \ \  \ \ \ \ S^{2-}

initial [ I]        0.091                                              0                                    0

Change [C]        -4x                                                 +x                                    + x

Equilibrium [E ]   0.091 - 4x                                      x                                        x

Here is  x is the amount in term of concentration that is lost by CN^-  and gained by   Ni(CN)_4 ^{2-}  and  S^{2-}

Gnerally the equilibrium constant for this reaction is mathematically represented as

              K_c  =  \frac{[Ni (CN)_4^{2-} ] [S^{2-} ] }{ [CN^{-}]^4}

=>             3.0*10^{12} =  \frac{x *  x}{ [0.091 - 4x ]^4}

=>              3.0*10^{12}*  [0.091 - 4x ]^4 = x^2

=>              [0.091 - 4x ]^4 =  \frac{x^2}{3.0*10^{12}}

=>              [0.091 - 4x ] = \sqrt[4]{ \frac{x^2}{3.0*10^{12}}}

=>              [0.091 - 4x ] = \frac{\sqrt{x} }{1316}

=>              119.8 - 5264x =\sqrt{x}

Square both sides

                 (119.8 - 5264x)^2 =x

=>               14352.04 - 1261255 x + 27709696x^2 = 0

=>                27709696x^2  - 1261255 x + 14352.04  = 0

Solving using quadratic equation

   The value of x  is  x =  0.0227  \  M

Hence the amount in terms of  molarity (concentration) of  Ni(CN)_4 ^{2-}  and  S^{2-} produced at equilibrium is x =  0.0227  \  M it then means that the amount of  NiS (nickel(II) sulfide) lost at equilibrium is  x =  0.0227  \  M

So the molar solubility of nickel(II) sulfide at equilibrium is  

        x =  0.0227  \  M

           

3 0
3 years ago
Which of the following increases the average kinetic energy of colliding particles
Solnce55 [7]
I'm pretty sure the answer is Temperature
5 0
3 years ago
1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.
maks197457 [2]

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in  of boron trifluoride? moles of fluorine.​

Explanation:

The molecular formula of boron trifluoride is BF_3.

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- 6.023x10^2^3 atoms.

Then, 2.20 moles of boron has

-=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

5 0
2 years ago
The Coriolis effect influences _____. neither wind speed nor wind direction wind speed both wind speed and wind direction wind d
Alona [7]

Answer: The correct answer is "wind direction".

Explanation:

Coriolis effect: This is an apparent deflection of moving air or water caused by the rotation of the earth.

Currents are created by wind. Their directions are determined by Coriolis effect.

Currents are created by wind. The earth is in constant motion. It describes the rotation of the earth which steers winds and the surface current. The ocean surface currents are deflected by Coriolis effect.

The direction of the wind blows from north and south towards equator.

Therefore, the Coriolis effect influences wind direction.

3 0
3 years ago
Read 2 more answers
Nonrenewable energy sources come out of the ground as liquids, gases,
elixir [45]

Answer:

TRUE

Explanation:

Production of Hydrocarbons from Natural Gas is as stated below:

Natural gas liquids include propane, butane, pentane, hexane, and heptane, but not methane and not <u>always</u> ethane, (<em>may include it </em><em><u>sometimes</u></em><em>.</em>) s<em>ince these hydrocarbons need refrigeration to be liquefied.</em>

4 0
2 years ago
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