Answer:
3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.
Explanation:
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
= Initial temperature of the substance
= Final temperature of the substance
We have mass of isopropyl alcohol = m = 25.0 g
Specific heat of isopropyl alcohol = c = 2.604 J/g°C
Initial temperature of the isopropyl alcohol = 
Final temperature of the isopropyl alcohol = 
Heat absorbed by the isopropyl alcohol to boil:
3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.
Answer:
Never store used oil in anything other than tanks and storage containers. Used oil may also be stored in units that are permitted to store regulated hazardous waste. Tanks and containers storing used oil do not need to be RCRA permitted, however, as long as they are labeled and in good condition.
The Bohr model proposed that electrons could just have characterized vitality levels thus when rotting back to a lower vitality level discharge a specific measure of vitality. Since the measure of vitality could be changed over to a specific recurrence then particular emanation lines were found in the electromagnetic range. Alternate speculations couldn't clarify the discharge lines.
Small ions have small areas. There is less resistance as they move through the solution.
For example, in molten salts, the conductivity of <span>Li+</span> is greater than that of <span>Cs+</span>.
Small ions have high charge density.
