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ELEN [110]
3 years ago
9

Ration for molar volume. 1 mole=___L at STP

Chemistry
1 answer:
solmaris [256]3 years ago
4 0

sorry idk!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11


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Which has the higher percentage of aluminum, Al2O, or Al(NO3)3
Rzqust [24]

Al₂O  has a higher percentage of aluminium.

Explanation:

To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:

Molar mass of Al₂O = 2(27) + 16 = 70g/mol

Molar mass of Al(NO₃)₃ = 27 + 3[14 + 3(16)] = 213g/mol

Percentage by mass of Al in Al₂O = \frac{2x27}{70} x 100 = 77%

Percentage by mass of Al in  Al(NO₃)₃ = \frac{27}{213} x 100 = 12.7%

Al₂O  has a higher percentage of aluminium.

learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

8 0
3 years ago
What is the mass of 21.7 moles of Al(NO3)3?
Elza [17]

Answer:I would say 21grams but i am not sure

Explanation:

5 0
2 years ago
16.4 mL of 0.135 M NaOH is used to neutralize 46.9 mL of HCl. The concentration of the HCl solution is ____ M (3 decimal places)
marshall27 [118]

The concentration of the HCl solution is 0.047 M.

Explanation:

Data given about acid and base:

volume of acid Vacid = 46.9 ml

molarity of acid =?

volume of the base (NaOH) = 16.4 ml

molarity of the base = 0.135 M

To know the concentration of the acid in this reaction, the formula used in titration  is used. It is

Macid X Vacid = Mbase X Vbase

the formula is rewritten as:

Macid = \frac{Mbase X Vbase}{Vacid}

putting the values in the equation:

Macid = \frac{0.135 X 16.4}{46.9}

          = 0.047 M

the concentration of the acid i.e HCl in the solution is of 0.047 M.

5 0
3 years ago
What is the wavelength of a light of frequency 6.42 x 1014 Hz?
Dahasolnce [82]

Answer:

467 nm is the answer

Explanation:

IT'S the answer for

8 0
3 years ago
Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b
Lelechka [254]

Answer:

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

Explanation:

A typical carbon–carbon bond requires 348 kJ/mol=348000 J/mol

Energy required to breakl sigle C-C bond:E

E=\frac{348000 J/mol}{6.022\times 10^{23} mol^{-1}}=5.7788\times 10^{-19} J

E=\frac{h\times c}{\lambda}

where,

E = energy of photon

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of the radiation

Now put all the given values in the above formula, we get the energy of the photons.

\lambda =\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{5.7788\times 10^{-19} J}

\lambda =3.4398\\times 10^{-7}m=343.98 nm

1 m = 10^{9} nm

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

4 0
3 years ago
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