Question

5) where 2 coins are toased find the probability of getting:

Answer 1

Step-by-step explanation:

Let S be the sample space

S={HH, HT, TH, TT}

n(S)= 4

A: both the coins with some place

B: both the coins with different place

C:at least one tail

D:at the most one head

1) A={TT,HH}

n(A)=2

P(G)= n(A)/n(S)

= 2/4

= 1/2

2) B ={HT, TH}

n(B) = 2

P(B) = n(B)/n(S)

= 2/4

= 1/2

3) C= {HT, TH, TT}

n(C)=3

P(C) = n(C)/n(S)

= 3/4

4). D={HT, TH}

n(D) = 2

P(D) = n(D)/n(S)

= 2/4

=1/2