I think the answer is A but i could be wrong
Distance=2m
because 200cm = 2m
so 4m-2m=2m
Answer:
The constant force exerted on the bullet is 1590.87 N.
Explanation:
It is given that,
Mass of the bullet, m = 8.6 g
Initial speed of the bullet, u = 0
Final speed of the bullet, v = 430.1 m/s
We need to find the force exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle. Let a is the acceleration of the bullet. So,
Let F is the force exerted. It is given by :
F = 1590.87 N
So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.
Answer:
259.456 J
Explanation:
Given that,
Work done on the system = 166 cal
The systam releases 954 J of thermal energy to its surroundings
We need to find the change in internal energy. It can be given by using the first law of thermodynamics as follows :
W = 166 cal = 694.544 (1cal = 4.184 J)
So, the change in internal energy of the system is 259.456 J.