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serious [3.7K]
3 years ago
12

How fast, relative to an observer, does an Empire ship have to travel for its markings to be confused with those of a Federation

ship? Use c for the speed of light in a vacuum.

Physics
1 answer:
Leni [432]3 years ago
5 0

Answer:

Speed of the spaceship = 1.92 x 10∧8 m/s

Explanation:

The solution is in the attach document.

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Which statement best describes a parallel circuit?
Anni [7]

Answer:a

Explanation:

Current increases as resistors are taken away

5 0
3 years ago
Can someone please explain to me in simple terms Einsteins theory of relativity, also known as time dialation?
alexira [117]

Answer:

Time dilation. Time dilation, in the theory of special relativity, the “slowing down” of a clock as determined by an observer who is in relative motion with respect to that clock.The world's most accurate clock has neatly shown how right Albert Einstein was 100 years ago, when he proposed that time is a relative concept and the higher you live above sea level the faster you should age. Einstein's theory of relativity states that time and space are not as constant as everyday life would suggest.The theory of relativity usually encompasses two interrelated theories by Albert Einstein: special relativity and general relativity. Special relativity applies to all physical phenomena in the absence of gravity. General relativity explains the law of gravitation and its relation to other forces of nature.

Explanation:

5 0
3 years ago
28. Multiple-Concept Example 5 reviews many of the concepts that play roles in this problem. An extreme skier, starting from res
Maksim231197 [3]

Answer: 7.78m/s

Explanation: As the the skier slide down the height, we assume the motion of a body, slidind down an incline plane.

Force down the plane= [email protected]

Frictional force= umg

u= coefficient of friction

Net force on skier = [email protected] umg

ma = [email protected]

a = g([email protected] - u) = 9.8 (sin 25- 0.2)

a = 9.8 × (0.4226-0.2) = 9.8 × 0.2226

a = 2.18m/s²

Using the formula V² = U² + 2aH

Where H = (10.4+ 3.5)=total height of descent before landing, U= 0.

V = √ 2 × 2.18× 13.9 = √60.604

V = 7.78m/s

5 0
3 years ago
Two identical spheres carry charges of +0.6 coulomb and -0.2 coulomb, respectively. If these spheres touch, the resulting charge
masya89 [10]

Answer:

2. +0.2 C

Explanation:

When the two spheres touch, the total charge will be redistributed such that the two spheres are at same potential:

V_1 = V_2

The potential can be rewritten as ratio between the charge on the sphere (Q) and the capacitance of the sphere (C):

\frac{Q_1}{C_1}=\frac{Q_2}{C_2}

Since the two spheres are identical, they have same capacitance:

C_1 =C_2=C

So we can write

\frac{Q_1}{C}=\frac{Q_2}{C}

Q_1=Q_2

And since the total charge is

Q=+0.6 C-0.2 C=+0.4 C

And this charge will be redistributed equally on the two spheres (Q_1 = Q_2), we have

Q_1 = Q_2 = \frac{Q}{2}=\frac{+0.4 C}{2}=+0.2 C

5 0
4 years ago
The difference in emf between the primary coil of a transformer and the secondary coil is directly related to the relative numbe
kirill115 [55]
True.

The more the coils either at the Primary or Secondary coils, the higher the Primary or Secondary Emf. The lower the coils at the Primary or Secondary coils, the lower the EMF at the Primary or Secondary.

Hence there is a direct relationship.
8 0
4 years ago
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