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3 years ago

Ba(NO3)2 What’s the atomic mass

Chemistry

1 answer:

Ahat [919]3 years ago

3 0

Answer:

261.337 g/mol

Explanation:

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What is your most convincing piece of evidence?

Sedaia [141]

Answer:

A magician I saw once made a painting of a dove come to life. The bird literally flew out of the painting.

That happened 10 years ago and I'm still wondering how that is even possible.

Explanation:

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3 years ago

Group 1A element sodium combines with Group 7A element chlorine to form sodium chloride or table salt. Based on this information

Ymorist [56]

The answer is Na < Cl

Chlorine is more electronegative than sodium because this follows the trend of the periodic table. The trend states that an element's electronegativity increases from left to right of a period and bottom to up of a group. Since sodium and chlorine are from the same period, and chlorine is at the right of sodium, chlorine is more electronegative.

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4 years ago

You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10

natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

<u><em>q = 3,14x10⁸ J of heat are required</em></u>

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = <em>18,8 kg of wood are required</em>

I hope it helps!

5 0

3 years ago

Can someone explain this to me, please?

zimovet [89]

Answer:

Isotopes have same atomic numbers, no. of protons and no. of electrons. Only their no. of neutrons and atomic mass are changed.

Atomic Mass = 24

Atomic No. = 11

Hence,

No. of protons in Na-24 = 11

No. of neutrons = Atomic Mass - Atomic Number

No. of neutrons = 24 - 11

No. of neutrons = 13

Atomic Number = 11

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

5 0

3 years ago

If 1.00 mol of argon is placed in a 0.500-L container at 30.0 ∘C , what is the difference between the ideal pressure (as predict

yan [13]

Answer:

The answer to your question is:

Explanation:

Ideal gases

PV = nRT

P = nRT / V

P = (1)(0.082)(303) / 0.5

P = 49.7 atm

Real pressure

P = V²(nRT)/ (V - nb) - an²

P = (0.5)²(1)(0.082)(303) / (0.5 - (1)(0.03219) - (1.345)(1)²

P = (6.2115)/(0.4678) - 1.345

P = 13.28 - 1.345

P = 11.93 atm

7 0

4 years ago