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Degger [83]
3 years ago
9

_Ca Brz+_Mg(NO3)2_Ca(NO3)2+_MgBr2 balancing equatios​

Chemistry
1 answer:
iren [92.7K]3 years ago
6 0
I think it’s legit 1 for all of them
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Which of the following compounds has the lowest percent gold content by mass which one has the highest percent gold content by w
IrinaVladis [17]
Highest percentage of gold by weight can be determined by looking at the atomic mass of the other elements in the compound. the smaller the total of mass of the other elements, the heigher the percentage of Au will be in that compound

a. AuOH, OH- = 17 gram/mole
b. Au(OH)3, 3 x OH- = 3 x 17 = 51 gram/mole
c. AuCl3 = 3x35.5= 106.5 gram/mole
d. AuI3 = 3x127 = 381 gram/mole


as we can see AuOH has the least Molecular mass, hence % of Au will be the highest compared to other choices

Answer: A
5 0
3 years ago
What is hybridization in chemistry? Give some example
dmitriy555 [2]

Answer:

Co2,so2

Explanation:

Hybridization is the mixing of atomic orbitals to form new hybrid orbitals.

Molecule shapes arise from how many hybrid orbitals the central atom uses and how they are arranged.

Don't read the all this but don't forget to leave a ❤

7 0
3 years ago
6.<br> What is the acceleration of a 24 kg mass pushed by a 6 N force?<br> I jus need number 6
Setler79 [48]

The acceleration : 0.25 m/s²

<h3>Further explanation</h3>

Given

mass = m = 24 kg

Force = F = 6 N

Required

The acceleration

Solution

Newtons' second law :

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

ΣF =  m x a

\large {\boxed {\bold {a = \frac {\sum F} {m}}}

Input the value :

6 N = 24 kg x a

a = 6 : 24

a = 0.25 m/s²

3 0
3 years ago
Read 2 more answers
How many protons electrons and neutrons does the following isotopes contain 1H+
Rus_ich [418]

Answer: 1 proton, 0 electron and 1 neutron are present in 1 H⁺ isotope.

8 0
3 years ago
The voltage for the following cell is +0.731 V. Find Kb for the organic base RNH2. Use EscE 0.241V.
tino4ka555 [31]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  value is   K_b  =   1.89 *10^{-6}

Explanation:

From the question we are told that

   The  voltage of the cell is  V  =  0.731 \  V

Generally K_b is mathematically represented as  

           K_b  =  \frac{K_w }{ K_a }

Where  K_w  is the equilibrium constant for this auto-ionization of water with a value  K_w  =  1.0 *10^{-14}

Generally the E_{cell} is mathematically represented as

       E_{cell} =  V  -  E_{SCE}

=>     E_{cell} =  0.731 - 0.241

=>       E_{cell} =   0.49 V

This  E_{cell} is mathematically represented as

             E_{cell} =  \frac{0.0592}{n} *  log K_a

Where n is the number of moles which in this question is  n = 1

         So  

         0.490 =  \frac{0.0592}{1}  *  log K_a

=>      K_a  =  5.30*10^{-9}

So  

     K_b  =  \frac{ K_w}{ K_a}

=>   K_b  =  \frac{1.0 *10^{-14}}{ 5.30*10^{-9}}

=>    K_b  =   1.89 *10^{-6}

5 0
3 years ago
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