Answer:
4.49 mmHg
Explanation:
Formula for osmotic pressure → π = M . R . T
M → molarity
Let's determine the moles of pepsin (mass / molar mass)
0.5 g / 35000 g/mol = 1.43 mol ×10⁻⁵ moles
These moles are in 60 mL of an aqueous solution. Let's determine M (mo/L)
1.43 mol ×10⁻⁵ mol / 0.060 L = 2.38×10⁻⁴ M
Noticed we changed the volume from mL to L → 60 mL . 1L/1000mL
T → T°K = T°C + 273 → 30°C +273 = 303K
Now we can put data on the formula:
π = 2.38×10⁻⁴ mol/L . 0.082 L.atm/mol.K . 303K
π = 5.91×10⁻³ atm
Let's convert the atm to mmHg
5.91×10⁻³ atm . 760mmHg / 1atm = 4.49 mmHg
I believe this process is called cellular respiration.
The answer is B because none of the other options are true.
The amount of heat needed to melt 423 g of water at 0°C is 141282 J
The heat required to melt water can be obtained by using the following formula:
<h3>Q = mL </h3>
Q is the heat required.
L is the latent heat of fusion (334 J/g)
m is the mass.
With the above formula, we can obtain the heat required to melt the water as illustrated below:
Mass of water (m) = 423 g
Latent heat of fusion (L) = 334 J/g
<h3>Heat (Q) required =? </h3>
Q = mL
Q = 423 × 334
<h3>Q = 141282 J</h3>
Therefore, the amount of heat needed to melt 423 g of water at 0°C is 141282 J
Learn more: brainly.com/question/17084080
Answer:
∴ The absolute pressure of the air in the balloon in kPa = 102.69 kPa.
Explanation:
- We can solve this problem using the general gas law:
<em>PV = nRT</em>, where,
P is the pressure of the gas <em>(atm)</em>,
V is the volume of the gas in L <em>(V of air = 6.23 L)</em>,
n is the no. of moles of gas <em>(n of air = 0.25 mole)</em>,
R is the general gas constant <em>(R = 0.082 L.atm/mol.K)</em>,
T is the temperature of gas in K <em>(T = 35 °C + 273 = 308 K</em>).
∴ P = nRT / V = (0.25 mole)(0.082 L.atm/mol.K)(308 K) / (6.23 L) = 1.0135 atm.
- <em>Now, we should convert the pressure from (atm) to (kPa).</em>
1.0 atm → 101.325 kPa,
1.0135 atm → ??? kPa.
∴ The absolute pressure of the air in the balloon in kPa = (101.325 kPa)(1.0135 atm) / (1.0 atm) = 102.69 kPa.
