
the oxidation number of carbon in MgCO3 = +IV
the oxidation number of carbon in CO2 = +IV
so, there is no change
Given parameters:
Weight of hydrated sample = 20g
Temperature = 250°C
Weight after cooling = 16.5g
Unknown:
Weight of water lost from the sample = ?
Solution:
The weight of water lost from the sample;
Weight of water lost = Weight of hydrated sample - Weight of dry sample
Weight of water lost = 20g - 16.5g = 3.5g
% of water in the sample = 
Input parameters solve;
= 
=17.5%
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)
Formula:

Solving:





Many scientist use dichotomous key