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weeeeeb [17]
2 years ago
7

Consider a standing wave on a string. What is the distance between two adjacent nodes in terms of the wavelength λ of the standi

ng wave?.
Physics
1 answer:
amid [387]2 years ago
3 0

The distance between the two adjacent nodes = λ/2.

<h3>What is Wavelength?</h3>

A periodic wave's wavelength is its spatial period, or the length over which its form repeats. It is a property of both travelling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings. The spatial frequency is the reciprocal of wavelength. The Greek letter lambda (λ) is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

The distance between the two adjacent nodes = λ/2.

for the standing wave ,the distance between any two adjacent nodes or antinodes is 1/2 λ.

to learn more about the wavelength go to - brainly.com/question/6297363

#SPJ4

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  x₁ = 0.62 m

Explanation:

In this exercise the force is electric, given by Coulomb's law

         F =k \frac{q_1q_2}{r^2}

This force is a vector, since the three charges are in a line we can reduce the vector sum to a scalar sum.

For the sense of force let us use that charges of the same sign repel and charges of the opposite sign attract.

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They ask us to find the point where the summaries of the force is zero.

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      k q₁q₂ / x² = k q₂q₃ / (d-x) ²

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let's solve

       d² - 2 x d + x² = \frac{q_3}{q_1}  x²

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       x² (1- 4/2) - 2 1.5 x + 1.5² = 0

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       x = [-3 ± \sqrt{ 3^2 + 4 \ 2.25}] / 2

       x = [-3 ± 4.24] / 2

       x₁ = 0.62 m

       x₂ = 3.62 m

since it indicates that the charge q₂ e places between the spheres, the correct solution is

            x₁ = 0.62 m

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