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stich3 [128]
3 years ago
15

Why you do scientists collect multiple trials?

Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

"When we do experiments it's a good idea to do multiple trials, that is, do the same experiment lots of times. When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events. Multiple trials can be done at one time."

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Calculate the magnitude and direction of the electric field 2.0 m from a long wire that is charged uniformly at λ = 4.0 × 10-6 C
Len [333]

Answer: 71.93 *10^3 N/C

Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

∫E*dr=Q inside/εo  Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

6 0
3 years ago
What is it when you divide the total distance traveled by the total time
alexdok [17]

This is called average speed.Its really simple

4 0
3 years ago
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snow_tiger [21]
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8 0
3 years ago
An elastic conducting material is stretched into a circular loop of 9.65 cm radius. It is placed with its plane perpendicular to
Nadya [2.5K]

Answer:

The induced emf in the coil is 0.522 volts.                        

Explanation:

Given that,

Radius of the circular loop, r = 9.65 cm

It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.

The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , \dfrac{dr}{dt}=-0.756\ m/s

Due to the shrinking of radius of the loop, an emf induced in it. It is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V

So, the induced emf in the coil is 0.522 volts.                                

8 0
3 years ago
If 12V battery maintains a 4.5A current through a resistor what is the resistance of the resistor?
Dimas [21]

Answer:

2.7ohms

Explanation:

Given parameters:

Voltage of the battery  = 12V

Current  = 4.5A

Unknown:

Resistance of the resistor  = ?

Solution:

From Ohm's law, we know that;

          V  = IR

V is the voltage

I is the current

R is the resistance

  So;

        R  = \frac{V}{I}   = \frac{12}{4.5}    = 2.7ohms

5 0
3 years ago
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