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prisoha [69]
2 years ago
7

Do you think it would be a good idea for a bumper car ride to have minimum and maximum weight requirements for riders? Apply New

ton's second and third laws of motion in your response.
Chemistry
1 answer:
grandymaker [24]2 years ago
3 0

Answer: If only max or min yes but if we have min and max that is a bad idea it is not as safe.

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How to solve this: a small dog has consumed a dangerous amount of apap. the vet has ordered: rx acetylcysteine 150mg/kg/stat. yo
Fantom [35]
Given:
Stock dose/concentration of 20% Acetylcysteine (200 mg/mL)
150 mg/kg dose of Acetylcysteine
Weight of the dog is 13.2 lb

First we must convert 13.2 lb to kg:
13.2 lb/(2.2kg/lb) = 6 kg

Then we must calculate the dose:
(150 mg/kg)(6kg) = 900 mg

Lastly, we must calculate the dose in liquid form to be administered:
(900 mg)/(200 mg/mL) = 4.5 mL

Therefore, 4.5 mL of 20% Acetylcysteine should be given.
3 0
3 years ago
Given that the formula of butane C4H10 the accepted value for the molar mass should be
deff fn [24]

Answer:

carbon mass = 12.01g/mol

hydrogen mass = 1.01g/mol

4 carbon atoms and 10 hydrogen so

12.01 x 4 + 1.01 x 10

48.04g/mol + 10.10g/mol

= 58.14g/mol

4 0
2 years ago
The carbon-14 content of a wooden harpoon handle found in an Inuit archaeological site was found to be 61.9% of the carbon-14 co
astraxan [27]

Answer:

3,964 years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

  • The half-life of the element is 5,730 years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(5,730 years) = 1.21 x 10⁻⁴ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 1.21 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 100%).

[A] is the remaining concentration of the sample ([A] = 61.9%).

∴ t = (1/k) ln([A₀]/[A]) = (1/1.21 x 10⁻⁴ year⁻¹) ln(100%/61.9%) = 3,964 years.

7 0
3 years ago
Both kepler's laws and newton's laws tell us something about the motion of the planets, but there are fundamental differences be
I am Lyosha [343]

Answer: See description

Explanation:

Kepler's laws have three principal points:

1. planets orbit the sun in elliptical paths

2. the orbial period is related to the orbital distance by T^{2} = d^3

where T is the orbital period and d is the orbital distance, T is in years and d is measured in units of the earth sun distance.

3. planets closer to the sun move faster than planets far away from it.

Newton:

Newton discovered that there is a consequence to the gravity exerted by objects: mass, the heavier the planet, the more gravitational force it posseses ( thats why we orbit the sun)

with the gravitational force F_{gravitational} =G \frac{Mm}{r^2} newton discovered the inverse-quadratic relationship between the distance of the planets and the acceleration exerted by the force one could exert on another.

Kepler's laws were mostly based on observed evidence with quantitative relationships between the mentioned variables. Newton's laws are based on calculus and symbolic equations. While Kepler's mode is basic, Newton took another step in and build a more general model for gravity (which was improved by general relativity later). In a nutshell Newton proved the scientific causes for Kepler's laws...

3 0
3 years ago
How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
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