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WITCHER [35]
2 years ago
9

A ticker timer makes 50 dots per second. When a body is pulled by a tap through the timer, the distance between the third and fo

urth dot is 3cm and the distance between the fourth and fifth dot is 4cm.what was the acceleration of the body?
Physics
1 answer:
fenix001 [56]2 years ago
8 0

Answer:

The acceleration is 1 cm/s^2.

Explanation:

The acceleration is defined as the rate of change of velocity.

Here, initial velocity, u = 3/1 = 3 cm/s

final velocity, v = 4/1 = 4 cm/s

time, t = 1 s

Let the acceleration is a.  

Use first equation of motion

v =  u + at

4 = 3 + 1 x a

a = 1 cm/s^2

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sergeinik [125]

v^2-{v_0}^2=2a(x-x_0)

dónde v es la velocidad de la esfera, v_0 es suya velocidad inicial, a=-g la aceleración debida a la gravedad, x la posición, y x_0 la posición inicial. Tomamos x_0=0\,\mathrm m a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)

\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}

Esto nos dice que la esfera alcanza una altura de 40 m en dos momentos - una vez hacia arriba y una vez hacia abajo. Sin embargo, independientemente del signo de la velocidad, sabemos que suya magnitud es 10 m/s, y así tenemos una rapidez de 10 m/s también en ambos momentos.

4 0
3 years ago
How do you solve <img src="https://tex.z-dn.net/?f=4x%5E%7B3%7D" id="TexFormula1" title="4x^{3}" alt="4x^{3}" align="absmiddle"
Vlad1618 [11]

Hello There!

Here's a explanation!

Let's solve your equation step-by-step.

4x^3=2x^-^1

4x^3=\frac{2}{x}

Step 1: Multiply both sides by x.

4x^4=2

\frac{4x^4}{4} =\frac{2}{4}

(Divide both sides by 4).

x^4=\frac{1}{2}

x=+(\frac{1}{2} )^(^\frac{1}{4} ^)

Take the root.

ANSWER!

x=0.840896 Or x=-0.840896

Hopefully, this helps you!!

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