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daser333 [38]
3 years ago
6

the roque requried to turn the crank on an ice cream maker is 4.50 N.m how much work does it take to turn the crank through 300

full turns
Physics
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

the work required to turn the crank at the given revolutions is 8,483.4 J

Explanation:

Given;

torque required to turn the crank, T = 4.50 N.m

number of revolutions, = 300 turns

The work required to turn the crank is given as;

W = 2πT

W = 2 x 3.142 x 4.5

W = 28.278 J

1 revolution = 28.278 J

300 revlotions = ?

= 300 x 28.278 J

= 8,483.4 J

Therefore, the work required to turn the crank at the given revolutions is 8,483.4 J

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Answer:

534.9 N

Explanation:

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A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of
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The acceleration of the air plane is 3.879 \mathrm{m} / \mathrm{s}^{2}

<u>Explanation:</u>

Given:

The mass of the air plane = 1492.3 kg

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The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

                         \text {Force }(F)=m \times \text { acceleration }(a)

The above equation can be written as below to find acceleration,

                        a=\frac{F}{m}

Now. Substitute the given values, we get,

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Leviafan [203]

Answer:

ω = 0.571 rad/s

Explanation:

given data

radius = 30 m

solution

we take here g = 9.8 m/s²

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put here value and we get

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b

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