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ASHA 777 [7]
3 years ago
8

Why do sea breezes occur during the day?

Physics
2 answers:
Sergio039 [100]3 years ago
7 0

Sea breezes occur during the day because solar radiation warms the land more than the water. This causes the warmer air over the land to rise. The resulting convection current causes wind to blow in from the sea.

Hatshy [7]3 years ago
6 0
The reason why is because the solar radiation warms land more than wind and because the unequal heating rates of land and water. Hope this helps :)
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Your house is 45.0 m from a powerline carrying 152 A of current. How much magnetic field does the current create at your house?
Sedaia [141]

This question involves the concepts of th magnetic field and current.

The magnetic field created by the current at the house is "6.75 x 10⁻⁷ T".

<h3>Magnetic Field</h3>

The magnetic field created by a current carrying wire can be given by the following formula:

B=\frac{\mu_o I}{2\pi r}

where,

  • B = magnetic field = ?
  • \mu_o= permeabiliy of free space =4π x 10⁻⁷
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B=\frac{4\pi x\ 10^{-7}(152)}{2\pi(45)}

B = 6.75 x 10⁻⁷ T

Learn more about magnetic field here:

brainly.com/question/23096032

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2 years ago
How does velocity differ from speed? What changes in motion can result in a change in velocity?
olga55 [171]
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4 0
3 years ago
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An incompressible fluid flows steadily through two pipes of diameter 0.15 m and 0.2 m which combine to discharge in a pipe of 0.
QveST [7]

Answer:

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Detailed explanation and calculation is shown in the image below

3 0
3 years ago
Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f
vampirchik [111]

Answer:

\large \boxed{\text{30 rev/s}}

Explanation:

This question is based on the Law of Conservation of Angular Momentum.

Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).

L = Iω

If momentum is conserved,

I₁ω₁ = I₂ω₂

Data:

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ω₁ = 6.0    rev·s⁻¹

 I₂ = 0.70 kg·m²s⁻¹

Calculation:

\begin{array}{rcl}I_{1}\omega_{1} &= &I_{2}\omega_{2}\\\text{3.5 kg$\cdot$m$^{2}$}\times \text{6.0 rev/s} &= &\text{0.70 kg$\cdot$m$^{2}$}\times\omega_{2}\\\text{21 rev/s} &= &0.70\omega_{2}\\\omega_{2} & = & \dfrac{\text{21 rev/s}}{0.70}\\\\&=&\textbf{30 rev/s}\\\end{array}\\\text{The skater's final rotational speed is $\large \boxed{\textbf{30 rev/s}}$}

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4 years ago
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