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3 years ago

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By detecting the subatomic particles emitted by weakly radioactive glucose as it is consumed by the brain, researchers are able

to obtain detailed images of activity both near the surface and below the surface of the brain. This technique is called a(n) Group of answer choices

1 answer:

Brut [27]3 years ago

4 0

Answer:CT scan

Explanation: CT(computerized Tomographic) Scan is a type of scan that is used to view bone fractures throughout the body by using a series of XRAYS which views from different angles. It has also been used to view complex bone fractures and injuries,liver enlargements,Heart diseases and cancers and other forms of tumors,it can also detect subatomic particles emitted by weakly radioactive glucose as it is consumed by the brain.

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People often use simple machines like pulleys, levers, and ramps because they say the machine “makes the work easier.” Which of

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I think the answer is D.
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2 years ago

A point charge of magnitude q is at the center of a cube with sides of length L

DanielleElmas [232]

Answer:

Explanation:

Answer is in the attachment below:

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3 years ago

The power in an electric circuit varies inversely with the resistance. If the power is 2,200 watts when the resistance is 25 ohm

valentinak56 [21]

Answer:

The value of resistance when power is 1100 watts = $R_{2}$ = 50 ohms

Explanation:

Power $P_{1}$ = 2200 Watts

Resistance $R_{1}$ = 25 ohms

Power $P_{2}$ = 1100 Watts

Resistance $R_{2}$ = we have to calculate

Given that the power in an electric circuit varies inversely with the resistance

⇒ P ∝ $\frac{1}{R}$

⇒ $\frac{P_{2} }{P_{1} }$ = $\frac{R_{1} }{R_{2} }$

⇒ $\frac{1100}{2200}$ = $\frac{25}{R_{2} }$

⇒ $R_{2}$ = 50 ohms

This is the value of resistance when power is 1100 watts.

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3 years ago

To analyze the motion of a body that is traveling along a curved path, to determine the body's acceleration, velocity, and posit

DiKsa [7]

To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as

$R = 350ft$

$a_t = 1.1ft/s^2$

PART A )

$a_c = \frac{V^2}{R}$

$a_c = \frac{V^2}{350}$

Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is $5.25ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$5.25 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$27.5625 = 1.21 + \frac{v^4}{122500}$

$v=42.3877ft/s$

Now calculate the angular velocity of the motorcycle

$v = r\omega$

$42.3877 = 350\omega$

$\omega = 0.1211rad/s$

Calculate the angular acceleration of the motorcycle

$a_t = r\alpha$

$1.1 = 350\alpha$

$\alpha = 3.1428*10^{-3}rad/s^2$

Calculate the time needed by the motorcycle to reach an acceleration of

$5.25ft/s^2$

$\omega = \alpha t$

$0.1211 = 3.1428*10^{-3}t$

$t = 38.53s$

PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is $6.75ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$45.5625 = 1.21 + \frac{v^4}{122500}$

$v=48.2796ft/s$

PART C)

Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is $21.5ft/s$

$a_r = \frac{v^2}{R}$

$a_r = \frac{21.5^2}{350}$

$a_r =1.3207ft/s^2$

Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is $21.5ft/s$

$a = \sqrt{a_t^2+a_r^2}$

$a = \sqrt{(1.1)^2+(1.3207)^2}$

$a = 1.7187ft/s^2$

PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is $6.75ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$45.5625 = 1.21 + \frac{v^4}{122500}$

$v=48.2796ft/s$

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3 years ago

Waves transfer energy by a series of

Elina [12.6K]

Answer:

Pushing molecules like a wave.

Explanation:

8 0

3 years ago

Read 2 more answers