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3 years ago

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By detecting the subatomic particles emitted by weakly radioactive glucose as it is consumed by the brain, researchers are able

to obtain detailed images of activity both near the surface and below the surface of the brain. This technique is called a(n) Group of answer choices

1 answer:

Brut [27]3 years ago

4 0

Answer:CT scan

Explanation: CT(computerized Tomographic) Scan is a type of scan that is used to view bone fractures throughout the body by using a series of XRAYS which views from different angles. It has also been used to view complex bone fractures and injuries,liver enlargements,Heart diseases and cancers and other forms of tumors,it can also detect subatomic particles emitted by weakly radioactive glucose as it is consumed by the brain.

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if the forces are moving in the same direction, ____ the forces. Please help i’m actually so confused!

jasenka [17]

Answer:

Explanation:

the directions may change

Or they will repel and become opposite sides

6 0

2 years ago

A 20 cm-radius ball is uniformly charged to 71 nC.

artcher [175]

Answer:

Part a)

$\rho = 2.12\mu C/m^3$

Part b)

$q_1 = 1.11 nC$

$q_2 = 8.88 nC$

$q_3 = 71 nC$

Part c)

$E_1 = 3996 N/C$

$E_2 = 7992 N/C$

$E_3 = 15975 N/C$

Explanation:

Part a)

As we know that charge density is the ratio of total charge and total volume

So here the volume of the charge ball is given as

$V = \frac{4}{3}\pi R^3$

$V = \frac{4}{3}\pi(0.20)^3$

$V = 0.0335 m^3$

now the charge density of the ball is given as

$\rho = \frac{71 nC}{0.0335} = 2.12\mu C/m^3$

Part b)

Now the charge enclosed by the surface is given as

$q = \rho V$

at radius of 5 cm

$q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.05)^3$

$q = 1.11 nC$

at radius of 10 cm

$q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.10)^3$

$q = 8.88 nC$

at radius of 20 cm

$q = 71 nC$

Part c)

As we know that electric field is given as

$E = \frac{kq}{r^2}$

so we have electric field at r = 5 cm

$E_1 = \frac{(9\times 10^9)(1.11 nC)}{0.05^2}$

$E_1 = 3996 N/C$

electric field at r = 10 cm

$E_2 = \frac{(9\times 10^9)(8.88 nC)}{0.10^2}$

$E_2 = 7992 N/C$

electric field at r = 20 cm

$E_3 = \frac{(9\times 10^9)(71 nC)}{0.20^2}$

$E_3 = 15975 N/C$

3 0

2 years ago

Which pigments are mixed to produce Blue?

romanna [79]

Answer:

Blue is produced when mixing cyan and magenta ( removing red and green)

5 0

3 years ago

What energy is the candle giving off

gregori [183]

The candle is giving off light
Chemical energy from the candle is converted to thermal energy

5 0

3 years ago

Two vectors A and B are at right angles to each other. The magnitude of A is 3.00. What should be the length of B, so that the m

AfilCa [17]

Answer: length of B =4.00

Explanation:

for the vectors A and B and the angle between them as x.

Magnitude of the sum of A and B is given as = √(A²+B²+2ABcosx

where

Magnitude of A = 3.00

Magnitude of the sum of A and B is 5.00

5.00=√(A²+B²+2ABcos90°

5.00= √3² +b² +0

5²= 3² +b²

25=9+b²

b²= 25-9

b² = 16

b= √16

b= 4

7 0

3 years ago