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lianna [129]
3 years ago
7

A thin film of oil of thickness t is floating on water. The oil has index of refraction no = 1.4. There is air above the oil. Wh

en viewed from the air in the direction normal to the surface, there is constructive interference of reflected red light with l = 675 nm. Find the minimum thickness t of the oil film that will give constructive interference of reflected light with l = 675 nm.
Physics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

t = 120.5 nm

Explanation:

given,    

refractive index of the oil = 1.4

wavelength of the red light = 675 nm

minimum thickness of film = ?

formula used for the constructive interference

2 n t = (m+\dfrac{1}{2})\lambda

where n is the refractive index of oil

t is thickness of film

for minimum thickness

m = 0

2 \times 1.4 \times t = (0+\dfrac{1}{2})\times 675

t = \dfrac{0.5\times 675}{2\times 1.4}

        t = 120.5 nm

hence, the thickness of the oil is t = 120.5 nm

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