A loudspeaker in a parked car is producing sound whose frequency is 20 510 Hz. A healthy young person with normal hearing is sta
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Complete question:
Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to the left slit than it is from the dot to the right slit? Fringe C is the central maximum.
Check the image uploaded.
Answer:
The difference is 1100 nm
Explanation:
A bright fringe creates constructive interference, the wavelength is always in a multiple form.
At center fringe, the difference is (550 nm)(0) = 0
For the first maximum, the difference is (550 nm)(1) = 550 nm
For the second maximum, the difference = (550 nm)(2) = 1100 nm
Thus, for nth maxima, the difference is (550 nm)(n)
From the image uploaded, C is located on the second maximum, therefore the difference is given as (550 nm)(2) = 1100 nm
Therefore, the dot on the screen in the center of fringe E to the left slit is 1100 nm
