It’s zero, I think. Because
3 doesn’t round up. It’s stays the same. But since there is nothing in the hundred place. It is 0.
-320. The negative sign represents loss. In all of the other cases, values are either being added or not changed at all.
The limit as a definite integral on the interval
on [2π , 4π] is
.
<h3>
What is meant by definite integral?</h3>
A definite integral uses infinitesimal slivers or stripes of the region to calculate the area beneath a function. Integrals can be used to represent a region's (signed) area, the cumulative value of a function changing over time, or the amount of a substance given its density.
Definite integral, a term used in mathematics. is the region in the xy plane defined by the graph of f, the x-axis, and the lines x = a and x = b, where the area above the x-axis adds to the total and the area below the x-axis subtracts from the total.
If an antiderivative F exists for the interval [a, b], the definite integral of the function is the difference of the values at points a and b. The definite integral of any function can also be expressed as the limit of a sum.
Let the equation be

substitute the values in the above equation, we get
=
on [2π, 4π],
simplifying the above equation

To learn more about definite integral refer to:
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Your simplified answer is indeed 2/3 (or 60%, or 0.6) because the fraction 24/36 can be simplified by dividing both the numerator and denominator by 6, which leaves you with 2/3.
If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.
For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.
Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.