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saul85 [17]
3 years ago
15

During a laboratory experiment, 9.68 g of iron reacted with excess sulfur to form 13.8 grams of iron II sulfide. Calculate the p

ercent yield of this experiment. What would be the percentage yield if the Theoretical yield was 15.2 grams?
Chemistry
1 answer:
Daniel [21]3 years ago
5 0

Answer:

Percent yield = 90.8%

Explanation:

The reaction of Fe with S to produce FeS is:

Fe + S → FeS

<em>Where the moles of Fe added in excess of S are the moles of FeS</em>

<em />

Now, percent yield is defined as 100 times the ratio between actual yield (13.8g of FeS) and theoretical yield (15.2g FeS):

Percent yield = 13.8g / 15.2g * 100

<h3>Percent yield = 90.8%</h3>
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What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

<u>Answer:</u> The theoretical yield of copper is 44.48 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of aluminium = 12.6 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol

The given chemical equation follows:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = \frac{3}{2}\times 0.467=0.7005mol of copper

Now, calculating the mass of copper  from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g

Hence, the theoretical yield of copper is 44.48 grams

4 0
3 years ago
A solution of acetic acid and water contains 205.0 g L-1 of acetic acid and 820.0 g L-1 of water. Compute the density of the sol
LekaFEV [45]

Answer:

\rho_t=1025000 gmL^{-1}

Explanation:

From the question we are told that:

Density of acetic acid \rho_a=205 gL^{-1}

Density of Water \rho_w=820 gL^{-1}

Generally the equation for Solution Density is mathematically given by

\rho_t= \rho_w+\rho_a

\rho_t=205+820

\rho_t=1025 gL^{-1}

\rho_t=1025000 gmL^{-1}

6 0
3 years ago
What’s is the answer
julsineya [31]

Answer:

The answer is the third one which is 24 (glucose)

3 0
3 years ago
What is the difference between solute and solvent
ratelena [41]

Answer:

A solvent is a substance which dissolves a solute. When a solvent dissolves into a solute, it creates a solution

5 0
3 years ago
Why is concentrated sulphuric acid is weak acid​
frez [133]

Answer:

Sulfuric acid is a strong acid in any state

Explanation:

You may be thinking if the definition that a weak acid produces relatively few ions in aqueous solution,

If you have 100 % sulfuric acid, there is no water, so the definition does not apply.

Commercial sulfuric acid contains about 2 % water. The sulfuric acid in that small amount of water consists of about 99 % HSO₄⁻ and 1 % SO₄²⁻. The acid is almost completely ionized.

Sulfuric acid is a strong acid.

7 0
3 years ago
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