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saul85 [17]
3 years ago
15

During a laboratory experiment, 9.68 g of iron reacted with excess sulfur to form 13.8 grams of iron II sulfide. Calculate the p

ercent yield of this experiment. What would be the percentage yield if the Theoretical yield was 15.2 grams?
Chemistry
1 answer:
Daniel [21]3 years ago
5 0

Answer:

Percent yield = 90.8%

Explanation:

The reaction of Fe with S to produce FeS is:

Fe + S → FeS

<em>Where the moles of Fe added in excess of S are the moles of FeS</em>

<em />

Now, percent yield is defined as 100 times the ratio between actual yield (13.8g of FeS) and theoretical yield (15.2g FeS):

Percent yield = 13.8g / 15.2g * 100

<h3>Percent yield = 90.8%</h3>
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For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) the equilibrium constant at a certain temperatur
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Answer:

Moles of NO₂ = 0.158

Explanation:

                         SO 2 ( g ) + NO 2 ( g ) ⇄  SO 3 ( g ) + NO ( g )

              According to the law of mass equation

                                     

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8 0
3 years ago
1. A gas has a volume of 45 L at a pressure of 140 kPa. What is the volume when
pishuonlain [190]

Answer:

The new volume of the gas is 21 L.

Explanation:

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7 0
3 years ago
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Answer:

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