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2 years ago

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During a laboratory experiment, 9.68 g of iron reacted with excess sulfur to form 13.8 grams of iron II sulfide. Calculate the p

ercent yield of this experiment. What would be the percentage yield if the Theoretical yield was 15.2 grams?

1 answer:

Daniel [21]2 years ago

5 0

Answer:

Percent yield = 90.8%

Explanation:

The reaction of Fe with S to produce FeS is:

Fe + S → FeS

<em>Where the moles of Fe added in excess of S are the moles of FeS</em>

<em />

Now, percent yield is defined as 100 times the ratio between actual yield (13.8g of FeS) and theoretical yield (15.2g FeS):

Percent yield = 13.8g / 15.2g * 100

<h3>Percent yield = 90.8%</h3>

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