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Anton [14]
3 years ago
6

Which statement describes an intensive property of matter

Chemistry
1 answer:
vaieri [72.5K]3 years ago
5 0

An intensive property is a property that does not depend on the amount of the substance in a system being measured. Examples are density and color. The opposite is called extensive where the properties depends on the amount of a substance.


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How much volume (in cm^3)is gained by a person who gains 11.8 lb of our fat? Human fat has a density of 0.918 g/cm^3
Zinaida [17]

The volume (in cm³) gained by a person who gains 11.8 lb of fat is 5830.49 cm³

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to convert pounds to grams </h3>

1 lb = 453.592 g

Therefore,

11.8 lb = 11.8 × 453.592

11.8 lb = 5352.3856 g

<h3>How to determine the volume </h3>
  • Mass = 5352.3856 g
  • Density = 0.918 g/cm³
  • Volume =?

Volume =  mass / density

Volume =  5352.3856 / 0.918

Volume = 5830.49 cm³

Learn more about density:

brainly.com/question/952755

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Answer:

Its not balanced

Explanation:

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List the elements and the amounts of each element below for 5 Li2S04.​
GREYUIT [131]

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Lithium has 5 elements, sulphur has 2 elements and oxygen has 4 elements

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Limestone is made of predominantly calcium carbonate. Geologists can test for limestone using hydrochloric acid. The products ar
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Copper can have improved wear resistance if alloyed with ceramic alumina, Al2O3. If a copper alloy has 7.7 wt % Al2O3, what is i
vitfil [10]

The composition in mol% of the elements are :

  • 4.91%  of Al₂O₃ in alloy  
  • 95.08% of Cu in alloy

<u>Given data : </u>

Weight percentage of copper alloy = 7.7 wt %

Assume weight of alloy = 100 grams

<h3>Applying the weight percentage </h3>

mass of Al₂O₃ in alloy = 7.7 gm

Mass of Cu in alloy = 100 - 7.7 = 92.3 gm

<u />

<u>First step : calculate the mole of elements</u>

i) moles of Al₂O₃ in alloy

 = mass of Al₂O₃  in alloy /  Atomic mass of Al₂O₃

 = 7.7 gm  / 102 gm/mol

 = 0.075 mol

ii) moles of Cu in alloy

 = mass of Cu in alloy / Atomic mass of Cu

 = 92.3 gm / 63.5 gm/mol

 = 1.45 mol

Therefore the total number of moles in the alloy = 0.075 + 1.45 = 1.525

<u>Next step : Determine the mole </u><u>percentages </u>

i) Mole percentage of Al₂O₃ in alloy  

= ( 0.075 ) / 1.525  * 100

= 4.91%

ii) Mole percentage of Cu in alloy

= ( 1.45 ) / 1.525 * 100

= 95.08%

<u />

Hence we can conclude that The composition in mol% of the elements are : 4.91%  of Al₂O₃ in alloy and  95.08% of Cu in alloy.

Learn more about alloys : brainly.com/question/716507

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2 years ago
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