Answer:
100 mL
Explanation:
Given data:
Mass of CaCO₃ produced = 2.00 g
Molarity of CaCl₂ = 0.200 M
Volume of CaCl₂ needed = ?
Solution:
Chemical equation:
Na₂CO₃ + CaCl₂ → 2NaCl + CaCO₃
First of all we will calculate the number of moles of CaCO₃.
Number of moles = mass/molar mass
Number of moles = 2.00 g / 100.09 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of CaCO₃ and CaCl₂.
CaCO₃ : CaCl₂
1 : 1
0.02 : 0.02
Thus, 0.02 moles of CaCl₂ react,
Volume of CaCl₂ reacted:
Molarity = number of moles / volume in L
0.200 M = 0.02 mol / volume in L
Volume in L = 0.02 mol / 0.200 M
Volume in L = 0.1 L
Volume in mL:
0.1 L × 1000 mL/1L
100 mL
Answer:
The amount of heat absorbed is <u>5.183889 kJ</u> .
Explanation:
In conversion of water to ice it rejects some heat while in conversion of ice to water it absorbs heat which is called latent heat which is given as 6.02 kJ/mol.
The amount of ice given is 15.5 g.
Converting it to moles as the latent heat is given in per moles:

Molecular mass of Hydrogen (H) and Oxygen (O) is 1 u and 16 u respectively.
Molecular mass of water is 18 g (
⇒ 2*1+16=18 ).
mole = 15.5/18 ≈ 0.8611 moles
Therefore the amount of heat absorbed by 15.5 g of ice ( 0.8611 moles) = <em>Latent heat * moles
</em>
Heat absorbed = 6.02*0.8611
= 6.02*(15.5/18)
≈ 5.183889 kJ
Hydrogen is a
covalent bond. (A bond where one or more pairs of electrons are shared by two atoms)
Answer : The number of moles present in ammonia is, 70.459 moles.
Solution : Given,
Mass of ammonia = 
Molar mass of ammonia = 17.031 g/mole
Formula used :


Therefore, the number of moles present in ammonia is, 70.459 moles.
Answer:
i) The bond angle decreases due to the presence of lone pairs, which causes more repulsion on the bond pairs and as a result, the bond pairs tend to come closer. ii) The repulsion between electron pairs increases with an increase in electronegativity of the central atom and hence the bond angle increases.
Explanation: