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3 years ago

7

Pitch marks are the invitations left by the ball when they fall on the green

1 answer:

Kipish [7]3 years ago

3 0

You can mark, lift and clean a ball on the green, but it's a violation to do so when another ball is in motion, as your ball might influence the outcome of that stroke. You can also mark and clean your ball in some instances when it's off the green: cleaning it, for example, just to the point where you can identify it.

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Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8

Kamila [148]

Answer:

34.6 m/s

Explanation:

From conservation of momentum, the sum of initial and final momentum are equal. Momentum is a product of mass and velocity. Initial mass will be 42.8+31.5+25.9=100.2 kg

Final mass will be 31.5+25.9=57.4 kg

From formula of momentum

M1v1=m2v2

Making v2 the subject of the formula then

$V2=\frac {M1v1}{m2}$

Substitute 100.2 kg for M1, 19.8 m/s fkr v1 and 57.4 kg for m2 then

$V2=\frac {100.2 kg\times 19.8 m/s}{57.4 kg}=34.56376 m/s\approx 34.6 m/s$

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3 years ago

When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic

Nuetrik [128]

Answer:

$8.1\cdot 10^{-4} C^{-1}$

Explanation:

The volumetric expansion of the liquid is given by

$\Delta V=\alpha V_0 \Delta T$

where

$\alpha$ is the coefficient of volume expansion

$V_0$ is the initial volume

$\Delta T$ is the change in temperature

For the liquid in this problem,

$V_0 = 2.35 m^3\\\Delta T=48.5^{\circ}C\\\Delta V=0.0920 m^3$

So we can solve the equation to find $\alpha$ :

$\alpha=\frac{\Delta V}{V_0 \Delta T}=\frac{(0.0920 m^3)}{(2.35 m^3)(48.5^{\circ}C)}=8.1\cdot 10^{-4} C^{-1}$

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4 years ago

Convert 2.4 milimetres into metre

AleksAgata [21]

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Milimetres are before centimetres and centimetres are before metres

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3 years ago

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sergey [27]

Explanation:

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3 years ago

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Arlecino [84]

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4 years ago